展开全部 代码如下: select * from tbl_DPImg where ID in (select min(ID) from tbl_DPImg group by DPID) 处理后结果为: 查找表中多余的重复记录,32313133353236313431303231363533e4b893e5b19e31333365666230重复记录是根据单个字段(teamId)来判断 sele
一个时间记录表,需要同时得到整个表或一段时间内第一条和最后一条两条记录,按如下方法会提示错误:ORDER BY clause should come after UNION not before select * from sdayXX order by op_date asc limit 1 union select * from sdayXX order by op_
mysql 8 WITH ranked_messages AS (SELECT m.*, ROW_NUMBER() OVER (PARTITION BY name ORDER BY id DESC) AS rnFROM messages AS m)SELECT * FROM ranked_messages WHERE rn = 1; mysql 8 以前写法 需求:账号表有多条相同的s