链接:https://www.nowcoder.com/practice/18ecd0ecf5ef4fe9ba3f17f8d00d2d66 分析: 当n为15的时候,可以用Math.min(c-n,n-b)来判断哪个是变成斐波那契数的最小步数。 public class Main {public static void main(String[] args) {Scanner i
Fibonacci Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 9156 Accepted: 6494 Description In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = Fn − 1 + Fn − 2 for n ≥ 2. For
【题目链接】:click here~~ 【题目大意】: In the Fibonacci integer sequence, F0 = 0, F1 = 1, andFn =Fn − 1 + Fn − 2 forn ≥ 2. For example, the first ten terms of the Fibonacci sequence are: 0, 1, 1, 2, 3, 5,
Fibonacci Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 9650 Accepted: 6856 Description In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = Fn − 1 + Fn − 2 for n ≥ 2. For
Fibonacci Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 1003 Accepted Submission(s): 264 Problem Description Following is the
fibonacci数列(二) 时间限制: 1000 ms | 内存限制: 65535 KB 难度: 3 描述 In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = Fn − 1 + Fn − 2 for n ≥ 2. For example, the first ten terms of the F
题意:矩阵快速幂取模 #include <iostream>#include <cstdio>#include <cstring>#include <cmath>using namespace std;long long mod;long long p[]={1,1,1,0};void matrix(long long a[],long long b[],long long c[]
Problem Description Fibonacci numbers are nice simple integers. All of you are familiar with it, aren’t you? The Fibonacci sequence <F[n]> are defined by the recurrence: F[0]=0; F[1]=1; F[n]=F[n
Fibonacci again and again Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3622 Accepted Submission(s): 1500 Problem Description 任何一个大学生对
题目描述A string s is LUCKY if and only if the number of different characters in s is a fibonacci number. Given a string consisting of only lower case letters , output all its lucky non-empty substrings i