80.网络游戏逆向分析与漏洞攻防-移动系统分析-利用数据包尝试穿墙

本文主要是介绍80.网络游戏逆向分析与漏洞攻防-移动系统分析-利用数据包尝试穿墙，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

免责声明：内容仅供学习参考，请合法利用知识，禁止进行违法犯罪活动！

如果看不懂、不知道现在做的什么，那就跟着做完看效果，代码看不懂是正常的，只要会抄就行，抄着抄着就能懂了

内容参考于：易道云信息技术研究院

上一个内容：79.利用数据包实现人物走路

码云版本号：b3e60d65ce177d331f3f842d7a7e72124663f2f8

代码下载地址，在 titan 目录下，文件名为：titan-利用数据包尝试穿墙.zip

链接：https://pan.baidu.com/s/1W-JpUcGOWbSJmMdmtMzYZg

提取码：q9n5

--来自百度网盘超级会员V4的分享

HOOK引擎，文件名为：黑兔sdk升级版.zip

链接：https://pan.baidu.com/s/1IB-Zs6hi3yU8LC2f-8hIEw

提取码：78h8

--来自百度网盘超级会员V4的分享

以 79.利用数据包实现人物走路 它的代码为基础进行修改

上一个内容里利用移动数据包实现了跟随功能，这个跟随功能不能越过障碍物，按理来说服务端是不可能有地图信息的，既然这游戏服务端有地图信息，接下来尝试突破它，这种操作实际上就是一个违规移动的操作，比如穿墙、飞天、遁地它们都是同样的操作

上一个内容里可以看到，只有从被跟随的角色客户端里才能看到 今晚打老虎 有移动的效果，用 今晚打老虎 的客户端看不到移动，这是因为，我们是直接发送的数据包，对于客户端而言移动是一个事件，是一个动作，我们只发了数据包并没有触发客户端里的事件、动作，所以只能从被跟随的角色里看到 今晚打老虎 自动移动的效果

被障碍物挡住无法前进，从下方的例子可以看出，服务端确实是有障碍物信息

https://live.csdn.net/v/386117

尝试硬走，也就是强制改变x、y的值，给服务端发送，成功实现穿越障碍物（穿墙），这可以看出坐标的数据服务器还是以客户端的数据为准

https://live.csdn.net/v/386116

如果不用数据包去逆向做这件事情，那就去找谁修改了坐标，然后在修改坐标附近的代码必定有一个if用来判断前方是否为障碍物，如果是那就不执行修改坐标这样的逻辑，找到这段逻辑，把if删除就能实现穿墙

CUIWnd_0.cpp文件的修改：修改了 loops函数

// CUIWnd_0.cpp: 实现文件
//#include "pch.h"
#include "htdMfcDll.h"
#include "CUIWnd_0.h"
#include "afxdialogex.h"
#include "extern_all.h"
#include "GameOBJECTDef.h"// CUIWnd_0 对话框
float _xNext = 0.0f;
float _yNext = 0.0f;
void _stdcall loops(HWND, UINT, UINT_PTR, DWORD) {PAIM aim = Client->GetAimByName(L"r");if (aim == nullptr) {return;}//AfxMessageBox(aim->Name);float xDis = fabs(Client->Player.x - aim->x);float hDis = fabs(Client->Player.h - aim->h);float yDis = fabs(Client->Player.y - aim->y);float xNext, yNext;int v[2]{ -1, 1 };if (xDis > 12) {// 强制修改角色x坐标的值Client->Player.x = Client->Player.x + 6 * v[Client->Player.x < aim->x];xNext = Client->Player.x;}else {xNext = aim->x;}if (yDis > 12) {// 强制修改角色y坐标的值Client->Player.y = Client->Player.y + 6 * v[Client->Player.y < aim->y];yNext = Client->Player.y;}else{yNext = aim->y;}if ((xDis < 2)&&(hDis < 2)&&(yDis < 2)) {Client->MoveStop(aim->x, aim->h, aim->y, 0.0f);}else {Client->MoveWalk(xNext,aim->h, yNext, 0.0f, 0.0f);}
}IMPLEMENT_DYNAMIC(CUIWnd_0, CDialogEx)CUIWnd_0::CUIWnd_0(CWnd* pParent /*=nullptr*/): CDialogEx(IDD_PAGE_0, pParent)
{}CUIWnd_0::~CUIWnd_0()
{
}void CUIWnd_0::DoDataExchange(CDataExchange* pDX)
{CDialogEx::DoDataExchange(pDX);
}BEGIN_MESSAGE_MAP(CUIWnd_0, CDialogEx)ON_BN_CLICKED(IDC_BUTTON1, &CUIWnd_0::OnBnClickedButton1)ON_BN_CLICKED(IDC_BUTTON2, &CUIWnd_0::OnBnClickedButton2)
END_MESSAGE_MAP()// CUIWnd_0 消息处理程序void CUIWnd_0::OnBnClickedButton1()
{// 发送坠落数据包Client->Fall();设置移动速度//float Speed = 50.0;//Client->SetProperty(Client->Player.lId, INDEX_MoveSpeed, &Speed);/*// 修改血量int HP = 10000000;Client->SetProperty(Client->Player.lId, INDEX_HP, &HP);*//*CString txt;txt.Format(L"通过AIM类获取角色信息 名字：%s，x坐标：%f", Client->Player.Name, Client->Player.x);AfxMessageBox(txt);*/// Client->HeartBeep();// Client->TalkTo(L"r", L"打架吗？");// Client->Talk(L"[欢迎来到麟科思]");// Client->SelectRole(L"今晚打老虎");/*Client->CreateRole(L"am4", 1.0, 2.0, 4.0, 8.0, "gui\BG_team\TeamRole\Teamrole_zq_humF_001.PNG","Face,0;Hat,0;Eyes,0;Beard,0;Ears,0;Tail,0;Finger,0;Cloth,0;Pants,0;Gloves,0;Shoes,0;Trait,0;HairColor,0;SkinColor,0;SkinMtl,0;Tattoo,0;TattooColor,16777215;","", 0.0);*///Client->SelectCamp("xuanrenZQ");//Client->StartCreateRole();//Client->DelRole(L"ranzhi11111");/*char buff[] = {0xA, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00,0x00, 0x00, 0x00, 0x00, 0x00, 0x4, 0x00, 0x02, 0x01, 0x00, 0x00, 0x00, 0x02, 0x01, 00 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0x37, 0x00, 0x37, 0x00, 0x37, 0x00, 0x37, 0x00, 0x37, 0x00, 0x37, 0x00, 0x37, 0x00, 0x37, 0x00, 0x37, 0x00, 0x38, 0x00, 0x00, 0x00, 0x02, 0x01, 0x00, 0x00, 0x00, 0x02, 0x01, 0x00, 0x00, 0x00};WinSock->OnRecv(buff, sizeof(buff));*/
}void CUIWnd_0::OnBnClickedButton2()
{::SetTimer(m_hWnd, 0x1000, 2000, loops);// 重新登录// Client->Backtoroles();
}

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