【运筹优化】拉格朗日松弛次梯度算法求解整数规划问题 + Java调用Cplex实战

本文主要是介绍【运筹优化】拉格朗日松弛次梯度算法求解整数规划问题 + Java调用Cplex实战，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

文章目录

一、拉格朗日松弛
二、次梯度算法
三、案例实战

一、拉格朗日松弛

当遇到一些很难求解的模型，但又不需要去求解它的精确解，只需要给出一个次优解或者解的上下界，这时便可以考虑采用松弛模型的方法加以求解。

对于一个整数规划问题，拉格朗日松弛放松模型中的部分约束。这些被松弛的约束并不是被完全去掉，而是利用拉格朗日乘子在目标函数上增加相应的惩罚项，对不满足这些约束条件的解进行惩罚。

拉格朗日松弛之所以受关注，是因为在大规模的组合优化问题中，若能在原问题中减少一些造成问题“难”的约束，则可使问题求解难度大大降低，有时甚至可以得到比线性松弛更好的上下界。

在这里插入图片描述

二、次梯度算法

由于拉格朗日对偶问题通常是分段线性的，这会导致其在某些段上不可导，所以没法使用常规的梯度下降法处理。于是引入次梯度（Subgradient）用于解决此类目标函数并不总是处处可导的问题。

次梯度算法的优势是比传统方法能够处理的问题范围更大，不足之处就是算法收敛速度慢。

在这里插入图片描述

三、案例实战

在这里插入图片描述

松弛之后的目标函数为

$:z=16x_1+10x_2+4x_4+\mu[10-(8x_1+2x_2+x_3+4x_4)]$

化简为

$:z=(16-8\mu)x_1+(10-2\mu)x_2+(-\mu)x_3+(4-4\mu)x_4+10\mu$

由于每一次迭代时 $\mu$ 是一个确定的常数，所以目标函数中的 $10\mu$ 可以在建模时省略

具体求解代码如下：

import ilog.concert.IloException;
import ilog.concert.IloIntVar;
import ilog.concert.IloLinearNumExpr;
import ilog.cplex.IloCplex;import java.util.Arrays;public class TestLR {// lambdastatic double lambda = 2d;// 最大迭代次数static int epochs = 100;// 上界最大未更新次数static int ubMaxNonImproveCnt = 3;// 最小步长static double minStep = 0.001;// 松弛问题模型static IloCplex relaxProblemModel;// 变量数组static IloIntVar[] intVars;// 最佳上下界static double bestLB = 0d;static double bestUB = 1e10;// 最佳拉格朗日乘数static double bestMu = 0d;// 最佳解static double[] bestX;// 运行主函数public static void run() throws IloException {//double mu = 0d;double step = 1d;int ubNonImproveCnt = 0;// 初始化松弛问题模型initRelaxModel();// 开始迭代for (int epoch = 0; epoch < epochs; epoch++) {System.out.println("----------------------------- Epoch-" + (epoch + 1) + " -----------------------------");System.out.println("mu: " + mu);System.out.println("lambda: " + lambda);// 根据mu，设置松弛问题模型目标函数setRelaxModelObjectiveBuMu(mu);if (relaxProblemModel.solve()) {// 获得当前上界（由于建模时没有考虑常数 10*mu，所以这里要加回来，得到松弛问题的真正目标值）double curUB = relaxProblemModel.getObjValue() + 10 * mu;// 更新上界if (curUB < bestUB) {bestUB = curUB;ubNonImproveCnt = 0;} else {ubNonImproveCnt++;}System.out.println("curUB: " + curUB);// 获取变量值double[] x = relaxProblemModel.getValues(intVars);// 计算次梯度double subGradient = (8 * x[0] + 2 * x[1] + x[2] + 4 * x[3]) - 10;double dist = Math.pow(subGradient, 2);// 迭迭代停止条件1if (dist <= 0.0) {System.out.println("Early stop: dist (" + dist + ") <= 0 !");break;}// 如果次梯度大于等于0，说明满足被松弛的约束，即可以作为原问题的可行解if (subGradient <= 0) {// 计算当前原问题的解值double obj = 16 * x[0] + 10 * x[1] + 4 * x[3];if (obj > bestLB) {// 更新下界bestLB = obj;bestMu = mu;bestX = x.clone();}}System.out.println("subGradient: " + subGradient);System.out.println("bestUB: " + bestUB);System.out.println("bestLB: " + bestLB);System.out.println("gap: " + String.format("%.2f", (bestUB - bestLB) * 100d / bestUB) + " %");// 迭代停止条件2if (bestLB >= bestUB - 1e-06) {System.out.println("Early stop: bestLB (" + bestLB + ") >= bestUB (" + bestUB + ") !");break;}// 上界未更新达到一定次数if (ubNonImproveCnt >= ubMaxNonImproveCnt) {lambda /= 2;ubNonImproveCnt = 0;}// 更新拉格朗日乘数mu = Math.max(0, mu + step * subGradient);// 更新步长step = lambda * (curUB - bestLB) / dist;// 迭代停止条件3if (step < minStep) {System.out.println("Early stop: step (" + step + ") is less than minStep (" + minStep + ") !");break;}} else {System.err.println("Lagrange relaxation problem has no solution!");}}}// 建立松弛问题模型private static void initRelaxModel() throws IloException {relaxProblemModel = new IloCplex();relaxProblemModel.setOut(null);// 声明4个整数变量intVars = relaxProblemModel.intVarArray(4, 0, 1);// 添加约束// 约束1：x1+x2<=1relaxProblemModel.addLe(relaxProblemModel.sum(intVars[0], intVars[1]), 1);// 约束2：x3+x4<=1relaxProblemModel.addLe(relaxProblemModel.sum(intVars[2], intVars[3]), 1);}// 根据mu，设置松弛问题模型的目标函数private static void setRelaxModelObjectiveBuMu(double mu) throws IloException {// 目标函数（省略了常数 10*mu）IloLinearNumExpr target = relaxProblemModel.linearNumExpr();target.addTerm(16 - 8 * mu, intVars[0]);target.addTerm(10 - 2 * mu, intVars[1]);target.addTerm(0 - mu, intVars[2]);target.addTerm(4 - 4 * mu, intVars[3]);if (relaxProblemModel.getObjective() == null) {relaxProblemModel.addMaximize(target);} else {relaxProblemModel.getObjective().setExpr(target);}}public static void main(String[] args) throws IloException {long s = System.currentTimeMillis();run();System.out.println("----------------------------- Solution -----------------------------");System.out.println("bestMu: " + bestMu);System.out.println("bestUB: " + bestUB);System.out.println("bestLB: " + bestLB);System.out.println("gap: " + String.format("%.2f", (bestUB - bestLB) * 100d / bestUB) + " %");System.out.println("bestX: " + Arrays.toString(bestX));System.out.println("Solve Time: " + (System.currentTimeMillis() - s) + " ms");}}

程序输出：

----------------------------- Epoch-1 -----------------------------
mu: 0.0
lambda: 2.0
curUB: 20.0
subGradient: 2.0
bestUB: 20.0
bestLB: 0.0
gap: 100.00 %
----------------------------- Epoch-2 -----------------------------
mu: 2.0
lambda: 2.0
curUB: 26.0
subGradient: -8.0
bestUB: 20.0
bestLB: 10.0
gap: 50.00 %
----------------------------- Epoch-3 -----------------------------
mu: 0.0
lambda: 2.0
curUB: 20.0
subGradient: 2.0
bestUB: 20.0
bestLB: 10.0
gap: 50.00 %
----------------------------- Epoch-4 -----------------------------
mu: 1.0
lambda: 2.0
curUB: 18.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-5 -----------------------------
mu: 11.0
lambda: 2.0
curUB: 110.0
subGradient: -10.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-6 -----------------------------
mu: 0.0
lambda: 2.0
curUB: 20.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-7 -----------------------------
mu: 4.0
lambda: 2.0
curUB: 42.0
subGradient: -8.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-8 -----------------------------
mu: 0.0
lambda: 1.0
curUB: 20.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-9 -----------------------------
mu: 1.0
lambda: 1.0
curUB: 18.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-10 -----------------------------
mu: 6.0
lambda: 1.0
curUB: 60.0
subGradient: -10.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-11 -----------------------------
mu: 0.0
lambda: 0.5
curUB: 20.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-12 -----------------------------
mu: 0.5
lambda: 0.5
curUB: 19.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-13 -----------------------------
mu: 3.0
lambda: 0.5
curUB: 34.0
subGradient: -8.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-14 -----------------------------
mu: 0.0
lambda: 0.25
curUB: 20.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-15 -----------------------------
mu: 0.1875
lambda: 0.25
curUB: 19.625
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-16 -----------------------------
mu: 1.4375
lambda: 0.25
curUB: 21.5
subGradient: -8.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-17 -----------------------------
mu: 0.0
lambda: 0.125
curUB: 20.0
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-18 -----------------------------
mu: 0.044921875
lambda: 0.125
curUB: 19.91015625
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-19 -----------------------------
mu: 0.669921875
lambda: 0.125
curUB: 18.66015625
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-20 -----------------------------
mu: 1.289306640625
lambda: 0.0625
curUB: 20.314453125
subGradient: -8.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-21 -----------------------------
mu: 0.206787109375
lambda: 0.0625
curUB: 19.58642578125
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-22 -----------------------------
mu: 0.22693252563476562
lambda: 0.0625
curUB: 19.54613494873047
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-23 -----------------------------
mu: 0.5265083312988281
lambda: 0.03125
curUB: 18.946983337402344
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-24 -----------------------------
mu: 0.6756666898727417
lambda: 0.03125
curUB: 18.648666620254517
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-25 -----------------------------
mu: 0.8154633045196533
lambda: 0.03125
curUB: 18.369073390960693
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-26 -----------------------------
mu: 0.9505987204611301
lambda: 0.015625
curUB: 18.09880255907774
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-27 -----------------------------
mu: 1.0159821063280106
lambda: 0.015625
curUB: 18.127856850624084
subGradient: -8.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-28 -----------------------------
mu: 0.7628945263568312
lambda: 0.015625
curUB: 18.474210947286338
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-29 -----------------------------
mu: 0.766863206459675
lambda: 0.0078125
curUB: 18.46627358708065
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-30 -----------------------------
mu: 0.7999655929725122
lambda: 0.0078125
curUB: 18.400068814054976
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-31 -----------------------------
mu: 0.833036974172046
lambda: 0.0078125
curUB: 18.333926051655908
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-32 -----------------------------
mu: 0.8658497429769483
lambda: 0.00390625
curUB: 18.268300514046103
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-33 -----------------------------
mu: 0.8821269422965887
lambda: 0.00390625
curUB: 18.235746115406823
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-34 -----------------------------
mu: 0.8982759667380851
lambda: 0.00390625
curUB: 18.20344806652383
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-35 -----------------------------
mu: 0.914361408369739
lambda: 0.001953125
curUB: 18.17127718326052
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-36 -----------------------------
mu: 0.9223725881222037
lambda: 0.001953125
curUB: 18.155254823755595
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-37 -----------------------------
mu: 0.9303523509964815
lambda: 0.001953125
curUB: 18.13929529800704
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-38 -----------------------------
mu: 0.9383164670353054
lambda: 9.765625E-4
curUB: 18.123367065929386
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-39 -----------------------------
mu: 0.9422907323175354
lambda: 9.765625E-4
curUB: 18.11541853536493
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
----------------------------- Epoch-40 -----------------------------
mu: 0.9462572201426962
lambda: 9.765625E-4
curUB: 18.107485559714608
subGradient: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
Early stop: step (9.896832958635996E-4) is less than minStep (0.001) !
----------------------------- Solution -----------------------------
bestMu: 2.0
bestUB: 18.0
bestLB: 10.0
gap: 44.44 %
bestX: [0.0, 1.0, 0.0, 0.0]
Solve Time: 152 ms

分析：
从最终结果可以看到， bestLB 为10，也就是通过拉格朗日松弛&次梯度算法得到的最优可行解的目标值为10，这明显不是最优解（最优解应该是16， $x_1=1$ ，其余变量为0）
这是因为我们松弛了一个约束，所以通过拉格朗日松弛&次梯度算法得到的解不一定是最优解。但是当遇到一些很难求解的模型，但又不需要去求解它的精确解时，拉格朗日松弛&次梯度算法就可以派上用场了！