Problem: 1193. 每月交易 I 👨🏫 参考题解 Code select DATE_FORMAT(trans_date, '%Y-%m') AS month,country,count(*) as trans_count,count(if(state = 'approved', 1, NULL)) as approved_count,sum(amount) as
偶数求和 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 26480 Accepted Submission(s): 11486 Problem Description 有一个长度为n(n<=100)的数列,该数列定义为从2开
递归定义;程序直接或间接调用自己,叫做递归。 成为递归的条件:1.要操作的数据规模一直减小,一般而言就是解决n问题必须解决n-1的问题2.必须有一个明确的终止条件。3.每一次的操作都相同,当前的数据和n-1个数据的关系都相同。 小例子: 1.用递归的思想求阶乘: #include<stdio.h> long fn(int n); int main() { int r;
给定矩阵A,令矩阵B里每个元素B[i][j]的值等于A[0][0]到A[i][j]子矩阵元素的和 class Solution(object):def CreateAMatrix(self,m,n):li_2d = [i for i in range(m)]print(li_2d)for i in range(m):li_2d[i] = [j for j in range(i*n+1,(i+
1、字符串拼接 getwords1 = input("请输入国家名字:")getwords2 = input("请输入首都名字:") print("您输入的是:"+getwords1+getwords2) 2、整数序列求和 getNum = eval(input("请输入数字:"))s = 0for i in range(getNum+1): s = s + i print(s)