比较简单; #include"stdio.h" #include"string.h" #define max 99999999 int map[300][300]; int min(int a,int b) { return a>b?b:a; } void flory(int m) { int i,j,k; for(k=0;k<m;k++) for(i=0;i<m;i++) fo
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1874 Problem Description 某省自从实行了很多年的畅通工程计划后,终于修建了很多路。不过路多了也不好,每次要从一个城镇到另一个城镇时,都有许多种道路方案可以选择,而某些方案要比另一些方案行走的距离要短很多。这让行人很困扰。 现在,已知起点和终点,请你计算出要从起点到终点,最短需要
题目: 畅通工程续 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 34450 Accepted Submission(s): 12600 Problem Description 某省自从实行了很多年的畅通
畅通工程续 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 36194 Accepted Submission(s): 13291 Problem Description 某省自从实行了很多年的畅通工程计划后,终于修建了很多
畅通工程续 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 36600 Accepted Submission(s): 13449 Problem Description 某省自从实
畅通工程续 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 13110 Accepted Submission(s): 4457 Problem Description 某省自从实行了很多年的畅通工程计划后,终