subsequences专题
ABC 362 E - Count Arithmetic Subsequences
原题链接：E - Count Arithmetic Subsequences 题意：给出长度为n的数组，要求找出所有的等差数列，并且按照长度递增输出。 思路：dp，因为是要找出等差数列，并且这题的数据量极小，所以可以考虑设计dp数组，dp[i][j][k][v]，i代表当前寻找的等差数列倒数第二项，j代表最后一项，k代表还需要寻找的长度，v代表当前判断的数，dp[i][j][k][v]代表以i
Split Array into Consecutive Subsequences问题及解法
问题描述： You are given an integer array sorted in ascending order (may contain duplicates), you need to split them into several subsequences, where each subsequences consist of at least 3 consecutive
HDU - 2227 Find the nondecreasing subsequences
题意：求不递减的子序列的个数 思路：跟昨天那题HDU-3030不同的是，昨天的是严格的递增的子序列数，稍微修改一下就行了 #include <iostream>#include <cstdio>#include <cstring>#include <algorithm>#define ll long longusing namespace std;const int MOD = 1
UVA 10069 Distinct Subsequences(dp + 高精度)
Problem E Distinct Subsequences Input: standard input Output: standard output A subsequence of a given sequence is just the given sequence with some elements (possibly none) left out. Formall
HDU 2227 Find the nondecreasing subsequences
题目链接~~> 做题感悟：开始想到用 2^n 这样来求子序列但是这样会多算很多（因为你不知道前面比它小的数的顺序是怎样的），很纠结看解题报告+自己理解用了一个晚上。 解题思路：注意：这题如果出现 1 1 1 结果也是 7，并不是 3 。这题需要用到DP 的思想，假设dp[ i ] 为 i 时a[i] 所形成的不递减子序列，那么dp[ i ] = sum ( dp[ j ] ) +1 (
【CF1924D】Balanced Subsequences 【卡特兰数，组合数，数学】
C F 1924 D . CF1924D. CF1924D.Balanced Subsequences 题意为：给定 n , m , k n,m,k n,m,k，求有多少个由 n n n 个 (， m m m 个 ) 组成的序列满足最长的合法括号子序列的长度恰为 2 k 2k 2k（对 1 0 9 + 7 10^9+7 109+7 取模）。 思路 我们很容易想到这跟 C a t
LeetCode - distinct-subsequences
题目： Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new string which is formed from the original string by deleting some (can be
Leetcode 3082. Find the Sum of the Power of All Subsequences
Leetcode 3082. Find the Sum of the Power of All Subsequences 1. 解题思路2. 代码实现 题目链接：3082. Find the Sum of the Power of All Subsequences 1. 解题思路 这一题的话其实反而还好，就是一个比较常规的动态规划的题目。 我们首先需要想明白一点，虽然题目中是要在所有的子序
LeetCode 940. Distinct Subsequences II
class Solution {public int distinctSubseqII(String S) {int[] dp=new int[S.length()];int res=0;for(int i=0;i<S.length();i++){dp[i]=1;for(int j=0;j<i;j++){if(S.charAt(i)!=S.charAt(j)){dp[i]+=dp[j];dp[i]
LeetCode 115. Distinct Subsequences
r a b b b i t 1 1 1 1 1 1 1 1 r 0 1 1 1 1 1 1 1 a 0 0 1 1 1 1 1 1 b 0 0 0 1 2 3 3 3 b 0 0 0 0 1 3 3 3 i 0 0 0 0 0 0 3 3 t 0 0 0 0 0 0 0 3 dp[i][j] =dp[i][j−1], s[j] != t[i] dp[i]
C#，最大公共子序列（LCS，Longest Common Subsequences）的算法与源代码
1 最大公共子序列 最长的常见子序列问题是寻找两个给定字符串中存在的最长序列。 最大公共子序列算法，常用于犯罪鉴定、亲子鉴定等等的 DNA 比对。 1.1 子序列 让我们考虑一个序列S=<s1，s2，s3，s4，…，sn>。 一个序列Z=<z1，z2，z3，z4，…，zm>在S上被称为S的子序列，当且仅当它可以从某些元素的S删除中派生出来时。 1.2 公共子序列 假设X和Y是
[ACM] SDUT 2607 Mountain Subsequences
Mountain Subsequences Time Limit: 1000ms Memory limit: 65536K 有疑问？点这里^_^ 题目描述 Coco is a beautiful ACMer girl living in a very beautiful mountain. There are many trees and flowers on the
Find the nondecreasing subsequences HDU 2227
树状数组 #include<iostream>#include<cstdio>#include<cstring>#include<algorithm>using namespace std;#define maxn 100006int a[maxn];int n=maxn;struct Note{int val,ord;}b[maxn];bool cmp(Not
【Codeforces Testing Round 12C】【DP 树状数组优化】Subsequences n个不同数，长度为m的LIS数
C. Subsequences time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output For the given sequence with n different elements find
Distinct Subsequences 挖坑待填 想不大明白这个最优子结构。。
http://blog.csdn.net/metaphysis/article/details/6862964 http://blog.csdn.net/lanxu_yy/article/details/17552789 待看
Codeforces Subsequences
题目： Karl likes Codeforces and subsequences. He wants to find a string of lowercase English letters that contains at least k subsequences codeforces. Out of all possible strings, Karl wants to find a s
Educational Codeforces Round 20 F. Coprime Subsequences（容斥）
原题链接：http://codeforces.com/contest/803/problem/F 题解： f[i]表示最大公约数为i的子序列的个数，我们可以求出所有公约数为i的倍数的子序列的个数，然后从后向前扫，对于每一个i，减去公约数为ki的（k>=2）的子序列的个数，最后可以得到答案。注意处理空集的情况。 #include<bits/stdc++.h>using nam
LeetCode491. Non-decreasing Subsequences
文章目录 一、题目二、题解 一、题目 Given an integer array nums, return all the different possible non-decreasing subsequences of the given array with at least two elements. You may return the answer in any
【Leetcode】115. Distinct Subsequences
Given two strings s and t, return the number of distinct subsequences of s which equals t. The test cases are generated so that the answer fits on a 32-bit signed integer. Example 1: Input: s = "ra
【打CF，学算法——四星级】CodeForces 689D Friends and Subsequences （RMQ+二分）
【CF简介】 提交链接：CF 689D 题面： D. Friends and Subsequences time limit per test 2 seconds memory limit per test 512 megabytes input standard input output standard output Mike and !