Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]Output: 5 思路1:DFS ,divide and conquer /*// Definition for a Node.class Node {public int v
Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 1、递归解法。两行 public int maxDept
Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 求二叉树的最小深度,最小深度定义为从根节点到最近的叶子节点经过的节点个
Question: Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 找二叉树的最大深度 Algorithm:
DFS-Depth First Search-深度优先搜索 对于一颗二叉树,深度优先搜索(Depth First Search)是沿着树的深度遍历树的结点,尽可能深的搜索数的分支。先访问根结点,然后遍历左子树接着是遍历右子树。 Ex:DFS遍历顺序为ABDCEF 我们可以用栈来实现它,栈-先进后出(first in last out),C++有栈的模版库。
题目: Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 题解: 基础中的基础。 /*** Definition
题目: Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 思路分析: 求二叉树的最小深度。二叉树多用迭代。 C++示例代
二叉树的最大深度 题目 给定一个二叉树,找出其最大深度。 二叉树的深度为根节点到最远叶子节点的距离。样例 给出一棵如下的二叉树: 这个二叉树的最大深度为3.题解 递归法 /*** Definition of TreeNode:* public class TreeNode {* public int val;* public TreeNode left, right
题目链接:https://leetcode.com/problems/minimum-depth-of-binary-tree/ 求树的最小深度,也就是说:沿着树的路径从根节点到最近叶节点的距离。 需要一个队列进行层次遍历(BFS,对层次进行计数),在某一层找到叶节点时返回。 class Solution {public static int minDepth(TreeNode root)
diffusers/controlnet-zoe-depth-sdxl-1.0 RuntimeError: Error(s) in loading state_dict for ZoeDepth:Unexpected key(s) in state_dict: 解决措施: Installing the right version of timm did the trick for me p