Implement int sqrt(int x). Compute and return the square root of x. 依然二分法….这道题虽然简单,但是有一些细节需要注意,我是提交了好几遍才通过的! 参考代码: class Solution {public:int mySqrt(int x) {if (x < 2) return x;int left = 1;int
Sqrt(x) Implement int sqrt(int x). Compute and return the square root of x. 算法思想: 1、二分法 class Solution {public:int sqrt(int x) {if(x < 0) return -1;long long target = (long long
Implement int sqrt(int x). Compute and return the square root of x. Subscribe to see which companies asked this question 二分法,最后再加一个处理 这么简单的题目竟然才做。。sigh class Solution(o
要求: Implement int sqrt(int x). Compute and return the square root of x. 注意:使用牛顿梯度法计算平方根,看百度百科或者维基百科 public int mySqrt(int x) {if (x== 0)return 0;double sol = 1;double res = 0;while(sol - re