saving专题

【HDU】5025 Saving Tang Monk 状压最短路

传送门:【HDU】5025 Saving Tang Monk 题目分析:这题一开始想都没想就敲了优先队列+dij。。然后TLE了。。。 后来发现是一个稀疏图。。换成spfa就过了。。 这是一个四维最短路,x轴,y轴,拿到第几个钥匙,打怪的状态(状压),然后就是很简单的状压最短路了。 要注意到钥匙不用状压,因为拿到钥匙是有顺序的。 代码如下: #include <c

06-1. Saving James Bond - Hard Version (30) BFS

06-1. Saving James Bond - Hard Version (30) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 CHEN, Yue This time let us consider the situation in the movie "Live

05-2. Saving James Bond - Easy Version (25)

05-2. Saving James Bond - Easy Version (25) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 CHEN, Yue This time let us consider the situation in the movie "Live

05-2. Saving James Bond - Easy Version

需要注意的是1.能否从中心岛跳到其他顶点,需要计算(0,0)到顶点的距离再减去小岛半径                          2.顶点到地点先把所有顶点转到到第一象限再判断方便一些 /* ***********************************************Author :fistyCreated Time :2015/1/1 22:

[状态压缩 广搜BFS]Saving Tang Monk

描述 《Journey to the West》(also 《Monkey》) is one of the Four Great Classical Novels of Chinese literature. It was written by Wu Cheng'en during the Ming Dynasty. In this novel, Monkey King Sun Wukong,

HDU 3037 Saving Beans 大组合数 lucas定理

直接lucas降到10w以内搞组合数 #include <cstdio>#include <cstring>typedef __int64 LL;LL f[110010];LL pow(LL a, LL b, LL c){LL ans = 1;while(b){if(b&1)ans = (ans*a) % c;b >>= 1;a = (a*a) % c;}return ans;}

hdu 5025 Saving Tang Monk[状态压缩bfs]( 2014 ACM/ICPC Asia Regional Guangzhou Online)

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5025 比赛的时候自己也在写这个。。但是,最后没有写出来。。不是自己写不出来。。只是,当时,思路已经很是混乱了。。表示心情很是糟糕。。其他队也已经a了。也没有心情写了。。很显然,自己比赛时的心态有待改观。。特别是正式的比赛中,心情应该比较平静。。。 题目意思: 孙悟空要救唐三藏,每杀一个蛇需要额外+

HDU - 5025 Saving Tang Monk

Problem Description 《Journey to the West》(also 《Monkey》) is one of the Four Great Classical Novels of Chinese literature. It was written by Wu Cheng'en during the Ming Dynasty. In this novel, Monke

Lates “error saving the project file” 解决办法

问题: 每次打开WinEdt都是空目录,关闭程序时提示“Error saving the project file:…” 解决方法: win7系统下,没有写入文件夹权限导致。Options -> Configuration Wizard -> User Profiles. 点击 Create User Profile 按钮 (all WinEdt configuration files

Android Saving Activity State使用说明和注意事项

1、说明 在管理activity生命周期的简单介绍中提到当一个activity被暂停或停止时,该activity的状态被保留。因为当activity对象被暂停或停止时仍然保留在内存中,所有有关成员的信息和当前的状态仍然可用。这样,用户对该activity所做的任何更改都会保留并当恢复时这些变化仍然存在。 然而,当系统为了恢复内存而销毁activity对象时,该activity对象就被销毁了,因

杭电2111-Saving HDU

Saving HDU Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4161    Accepted Submission(s): 1892 Problem Description 话说上回讲到海东集团面临内外交困,

Saving Time and Money Using SAS

版权声明:原创作品,允许转载,转载时请务必以超链接形式标明文章原始出版、作者信息和本声明。否则将追究法律责任。 http://blog.csdn.net/topmvp - topmvp Get the most from your SAS software! In this expert collection of strategic and tactical solutions, autho

Saving James Bond HDU - 1245(多源点 floyd)

This time let us consider the situation in the movie “Live and Let Die” in which James Bond, the world’s most famous spy, was captured by a group of drug dealers. He was sent to a small piece of land

ACM/ICPC 2018亚洲区预选赛北京赛站网络赛 Saving Tang Monk II —— dijkstra+优先队列

描述 《Journey to the West》(also 《Monkey》) is one of the Four Great Classical Novels of Chinese literature. It was written by Wu Cheng’en during the Ming Dynasty. In this novel, Monkey King Sun Wukong, p

PTA Saving James Bond - Easy Version 思路分析及代码解析

PTA 7-10 Saving James Bond - Easy Version 思路分析及代码解析 v1.0 一、前导1. 需要掌握的知识2. 题目信息 二、解题思路分析1. 题意理解2. 思路分析(重点) 三、具体实现1. 弯路和bug2. 代码框架(重点)2.1 采用的数据结构2.2 程序主体框架2.3 各分支函数 3. 完整编码 四、参考资料 一、前导 1. 需要掌握的

MT6735[CTS Verifier][Test Method] Battery Saving Mode Test

[DESCRIPTION] Bettery Saving Mode Test [SOLUTION] 资料来源:一牛网论坛 MT6735 原文地址:http://bbs.16rd.com/thread-454176-1-1.html

7-10 Saving James Bond - Easy Version (25分)

借鉴代码 注意临界值,如果007可以跳跃的长度与两个点之间的距离刚好相等,则也可以跳。 这个代码对借鉴代码有点改进。 #include <cstdio>#include <cmath>#include <iostream>#include <string>#include <vector>#include <cstring>#include <algorithm> #include

Lpl and Energy-saving Lamps 计蒜客

https://nanti.jisuanke.com/t/30996 暴力跑一遍每个月 再暴力跑一遍房间序列 看以当前灯泡数量能换哪个房间 维护区间最小值 线段树二分查找 最多1e5个房间 都换完了就直接退出 #include<bits/stdc++.h>using namespace std;#define ll long longconst ll N=0x3f3f3f3f3f3f3

hdu5025 (2014广州网赛1004)Saving Tang Monk

题意:类似走迷宫的一个题,给一个n*n的地图,从K开始走到T,标#号的地方不能走。走的过程中,要按顺序拿m种钥匙(在地图中是数字,每种可能有多把),如果遇到蛇S,需要花1的额外时间把它打死。输出走到终点的最短时间。         思路:状态空间搜索。如果把钥匙的取得情况和蛇的生存情况也看成状态,就简单多了。状态第一、二维是行和列。钥匙最多9,需要按顺序拿,所以第三维开10就足够

夏令时【Daylight Saving Time】时间计算出错的解决办法

纠结了好几天,今天终于找到了解决办法,赶快分享一下: 在夏令时时区会出现的情况: 1、非夏令时: 2、夏令时: 3、Code:        同样是两个时间相减,为什么夏令时和非夏令时不一样的,这实际上就是夏令时的规则,大概在每年的3月底,夏令时会自动将系统时钟跳快一小时,具体操作就是当时钟走到1:59时,下一刻是3:00;如果是夏令时改成非夏令时一般是在11月初,当时钟走到

浙大数据结构:拯救007,06-图2 Saving James Bond - Easy Version (25 分)

06-图2 Saving James Bond - Easy Version (25 分) This time let us consider the situation in the movie “Live and Let Die” in which James Bond, the world’s most famous spy, was captured by a group of drug

七、图(中):Saving James Bond - Hard Version

目录 题目描述代码出现的问题和解决方法 题目描述 This time let us consider the situation in the movie “Live and Let Die” in which James Bond, the world’s most famous spy, was captured by a group of drug dealers. He

六、图(上):Saving James Bond - Easy Version

目录 题目描述代码注意事项 题目描述 This time let us consider the situation in the movie “Live and Let Die” in which James Bond, the world’s most famous spy, was captured by a group of drug dealers. He was se

07-图5 Saving James Bond - Hard Version (30分)

07-图5 Saving James Bond - Hard Version (30分) This time let us consider the situation in the movie “Live and Let Die” in which James Bond, the world’s most famous spy, was captured by a group of drug

06-图2 Saving James Bond - Easy Version (25分)

06-图2 Saving James Bond - Easy Version (25分) This time let us consider the situation in the movie “Live and Let Die” in which James Bond, the world’s most famous spy, was captured by a group of drug

执行docker login 时报错Error saving credentials: error storing credentials

问题 按照docker官网文档把image推到docker hub仓库时,在执行docker login -u [username]时报错: Error saving credentials: error storing credentials - err: exit status 1, out: `Post "https://hub.docker.com/v2/users/login?ref