poj3070专题
poj3070--Fibonacci(矩阵的快速幂)
Fibonacci Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 9650 Accepted: 6856 Description In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = Fn − 1 + Fn − 2 for n ≥ 2. For
矩阵快速幂 求斐波拉切数列的第n项 poj3070
Fibonacci Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 7241 Accepted: 5131 Description In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = Fn − 1 + Fn − 2 for n ≥
【算法学习】POJ3070——利用分治法来计算Fibonacci数列的值
Description In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = Fn − 1 + Fn − 2 for n ≥ 2. For example, the first ten terms of the Fibonacci sequence are: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, …
POJ3070 矩阵快速幂模板题
题解： 我学习矩阵快速看的是这个博客： http://blog.csdn.net/nyist_tc_lyq/article/details/52981353# 时隔3个月再来学这个矩阵快速幂，我以为我当初已经是理解了模板的，果然我还是个笑话，压根只是会套模板，根本不知道是干嘛的玩意这个代码。一直纠结了一早上都不知道为什么会得出可以得到这个结果的，而且为你们可以先看看上面的博客，然后再看下我自
[POJ3070]Fibonacci
Fibonacci Time Limit: 1000MS Memory Limit: 65536K Description In the Fibonacci integer sequence, F0 = 0, F1 = 1, and Fn = Fn − 1 + Fn − 2 for n ≥ 2. For example, the first ten terms of the Fibonacc