maximum专题

leetcode#628. Maximum Product of Three Numbers

题目 Given an integer array, find three numbers whose product is maximum and output the maximum product. Example 1: Input: [1,2,3]Output: 6 Example 2: Input: [1,2,3,4]Output: 24 Note: The lengt

Maximum likelihood function maximizes what thing?

最大似然函数(Maximum Likelihood Function)最大化的是数据在给定参数下出现的概率。具体来说,它最大化的是似然函数(Likelihood Function),即给定参数 ( \theta ) 下观测数据的概率。在统计学中,似然函数 ( L(\theta) ) 通常定义为所有独立观测数据点概率的乘积,对于参数 ( \theta ) 的函数。 对于一组独立同分布的观测数据

ORA-24067: exceeded maximum number of subscribers for queue ADMIN.SMS_MT_QUEUE

临时处理办法: delete from aq$_ss_MT_tab_D;delete from aq$_ss_MT_tab_g;delete from aq$_ss_MT_tab_h;delete from aq$_ss_MT_tab_i;delete from aq$_ss_MT_tab_p;delete from aq$_ss_MT_tab_s;delete from aq$

[LeetCode] 239. Sliding Window Maximum

题:https://leetcode.com/problems/sliding-window-maximum/description/ 题目 Given an array nums, there is a sliding window of size k which is moving from the very left of the array to the very right. You

vue3 el-menu 菜单Maximum recursive updates exceeded 报错

vue3 用el-menu实现管理后台左侧菜单,报Uncaught (in promise) Maximum recursive updates exceeded in component <ElMenu>. This means you have a reactive effect that is mutating its own dependencies and thus recursivel

浙大数据结构:01-复杂度2 Maximum Subsequence Sum

数据结构MOOC PTA习题 01-复杂度2 Maximum Subsequence Sum #include <iostream>using namespace std;const int M = 100005;int a[M];int main(){int k;cin >> k;int f = 1;for (int i = 0; i < k; i++){cin >> a[i

Maximum Index

Given an array arr[], find the maximum j – i such that arr[j] > arr[i] Given an array arr[], find the maximum j – i such that arr[j] > arr[i]. Examples: Input: {34, 8, 10, 3, 2, 80, 30, 33, 1}O

Maximum Number in Mountain Sequence

Given a mountain sequence of n integers which increase firstly and then decrease, find the mountain top. Example Example 1: Input: nums = [1, 2, 4, 8, 6, 3] Output: 8 Example 2: Input: nums = [

Maximum Depth of N-ary Tree

Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]Output: 5 思路1:DFS ,divide and conquer /*// Definition for a Node.class Node {public int v

Maximum Length of Repeated Subarray

Given two integer arrays A and B, return the maximum length of an subarray that appears in both arrays. Example 1: Input:A: [1,2,3,2,1]B: [3,2,1,4,7]Output: 3Explanation: The repeated subarray

Path With Maximum Minimum Value

Given a matrix of integers A with R rows and C columns, find the maximum score of a path starting at [0,0] and ending at [R-1,C-1]. The score of a path is the minimum value in that path.  For example

leetcode104 Maximum Depth Of Binary Java

Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 1、递归解法。两行 public int maxDept

Leetcode83: Maximum Subarray

Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array [−2,1,−3,4,−1,2,1,−5,4], the contiguous subarray [4,−1,2,1] h

hdu5052 Yaoge’s maximum profit 树链剖分

一棵树上,从u走到v,在某点买入,咋之后的某点卖出,求最大利润。 维护正着走和反着走的最大利润。 #include<iostream>#include<cstdio>#include<cmath>#include<algorithm>#include<cstring>#include<vector>#include<set>#include<map>#include<que

Ural 1146 Maximum Sum(DP)

题目地址:Ural 1146 这题是求最大子矩阵和。方法是将二维转化一维。 首先用n*n的方法来确定矩阵的列。需要先进行预处理,只对每行来说,转化成一维的前缀和,这样对列的确定只需要前后两个指针来确定,只需要用前缀和相减即可得到。前后两个指针用n*n的枚举。 确定好了哪几列,那么再确定行的时候就转化成了一维的最大连续子序列的和。再来一次O(n)的枚举就可以。 这样,总复杂就变成了O(n^3

leetcode Maximum Subarray 最大子序列

Maximum Subarray  Total Accepted: 28381 Total Submissions: 83696 My Submissions Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example

Codeforces Round #259 (Div. 2) C Little Pony and Expected Maximum

用逆向思维解+容斥原理 最大为 m 个的概率为 1减去不是m最大的概率,(1 - (( m-1 )/ m ) ^ n ),则 m-1 的概率为 在 不是 m 的状态下 乘以 1减去不是m-1最大的概率 以此类推 感谢楠哥的思路 #include <algorithm>#include <iostream>#include <iomanip>#include <cstring>#

解决GitBook RangeError: Maximum call stack size exceeded

问题描述 在编写Gitbook的过程中,在启动gitbook serve预览的时候,发生了错误RangeError: Maximum call stack size exceeded。 解决方案 https://github.com/GitbookIO/plugin-lunr/blob/master/README.md#limitations l

***Binary Tree Maximum Path Sum

题目: Given a binary tree, find the maximum path sum. For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connection

洛谷 CF1985B Maximum Multiple Sum 题解

题目翻译 给定一个 n n n,寻找一个 x x x 使得: 2 ≤ x ≤ n 2\le x\le n 2≤x≤n。所有小于等于 n n n 的 x x x 的倍数的和最大。 输出这个 x x x。 本题每个样例有 t t t 组测试数据。 思路 对于这道题,可以枚举 x x x 的值,找到符合要求的 x x x。 显然,对于每一个 x x x 直接暴力累加倍数

【PAT】【Advanced Level】1007. Maximum Subsequence Sum (25)

1007. Maximum Subsequence Sum (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given a sequence of K integers { N1, N2, ..., NK }. A continuous

Leetcode 3186. Maximum Total Damage With Spell Casting

Leetcode 3186. Maximum Total Damage With Spell Casting 1. 解题思路2. 代码实现 题目链接:3186. Maximum Total Damage With Spell Casting 1. 解题思路 这一题就是一个简单的动态规划的题目,我们只需要考虑每一个位置上的元素取或者不取即可: 如果不取,直接考察下一个元素即可;如果取,考察能

Fatal error: Maximum execution time of 30 seconds exceeded in

Fatal error: Maximum execution time of 30 seconds exceeded inj报错解决方法 第一种解决办法 找到php的配置文件php.ini 修改max_execution_time = 30  为 max_execution_time = 300(这个值根据情况更改 大于30即可) 重启服务器apache 第二种解决办法

Maximum function nesting level of '100' reached, aborting!--漫谈递归:PHP里的尾递归及其优化

Maximum function nesting level of '100' reached, aborting! 不同的语言对尾递归的支持都有所不同,编译器的优化也不尽相同。我们之前看了C语言的尾递归,那么在PHP里又是如何的呢? PHP对尾递归没有优化效果 先来看下实验。 01<?php 02function factorial($n) 03{ 04    i

ValueError: Maximum allowed size exceeded

这个错误是因为你尝试创建的数组`M`过大,超出了内存限制。你需要重新定义`M`的范围,使其在合理的内存范围内。 解决方法 **使用生成器**:    - 如果你只需要在循环中逐一处理这些值,可以使用生成器表达式,而不是一次性生成整个数组:      def large_range(start, end, step):          while start < end:

Unity Maximum Allowed Timestep的说明

Maximum Allowed Timestep的说明 关于Maximum Allowed Timestep这个配置的说明,Unity有一份官方的说明。 Time-maximumDeltaTime - Unity 脚本 API 结合Unity的函数执行顺序,我们可以简单理解为: FixedUpdate在1次Update可能会执行N次,N约等于Time.deltaTime / Time.fi