lowest专题

Binary Tree - Lowest Common Ancestor 题型总结

Lowest Common Ancestor of a Binary Search Tree 思路:这题跟 Lowest Common Ancestor of Binary Tree 一模一样。思路:就是找p的节点在不在左支,或者右支,找到各自左右节点,然后进行比较,如果两者不一样,说明当前的root就是lowest 父节点,如果左边为空,那就都在右边,返回右边的即可,如果右边为空,那就都在左

HDU2028 Lowest Common Multiple Plus【stein算法】【水题】

Lowest Common Multiple Plus Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 36800    Accepted Submission(s): 15116 Probl

1106 Lowest Price in Supply Chain (25分) C++

1106 Lowest Price in Supply Chain 题目描述解题思路代码 题目描述 A supply chain is a network of retailers(零售商), distributors(经销商), and suppliers(供应商)-- everyone involved in moving a product from supplier to

72【leetcode】经典算法- Lowest Common Ancestor of a Binary Search Tree(lct of bst)

题目描述: 一个二叉搜索树,给定两个节点a,b,求最小的公共祖先 _______6______/ \___2__ ___8__/ \ / \0 _4 7 9/ \3 5 例如: 2,8 ---->6 2,4----->2 原文描述: Given a b

LeetCode-207. Course Schedule 236. Lowest Common Ancestor of a Binary Tree 210. Course Schedule

207. Course Schedule class Solution {public static int[] visitStatus;public static ArrayList<ArrayList<Integer>> adjList;//邻接表public boolean canFinish(int numCourses, int[][] prerequisites) {adjList=

2021年度训练联盟热身训练赛第二场 J-Lowest Common Ancestor 进制转换,LCA

题目链接 https://ac.nowcoder.com/acm/contest/12794/J 题意 满二叉树,层序遍历给出编号,多次询问求两点公共祖先。其中点编号以十六进制串给出(1000位),输出也是十六进制 思路 满二叉树层序遍历的LCA没什么好说的,对于u和v,一直对u和v编号大的除二,直到相等就找到了 看到十六进制,加上直接除二这个操作就别考虑十进制数了,用二进制串处理,二

LeetCode 236 Lowest Common Ancestor of a Binary Tree (LCA)

Follow up for problem "Populating Next Right Pointers in Each Node". What if the given tree could be any binary tree? Would your previous solution still work? Note: You may only use constant extra

[LeetCode]236.Lowest Common Ancestor of a Binary Tree

题目 Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree.According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two node

Lowest Unique Price (第六届省赛)map

/*此题一定是一个大模拟map*/#include <iostream>#include <cstdio>#include <cstring>#include <algorithm>#include <map>using namespace std;int main(){int t;scanf("%d", &t);while(t--){map <int, int> s;s.clear()

236. Lowest Common Ancestor of a Binary Tree

236. Lowest Common Ancestor of a Binary Tree 给定一个二叉树, 找到该树中两个指定节点的最近公共祖先。 百度百科中最近公共祖先的定义为:“对于有根树 T 的两个结点 p、q,最近公共祖先表示为一个结点 x,满足 x 是 p、q 的祖先且 x 的深度尽可能大(一个节点也可以是它自己的祖先)。” 例如,给定如下二叉树:  root = [3,5,

PAT甲级1106 Lowest Price in Supply Chain:[C++题解]树、结点到根结点的距离、树形dp、记忆化搜索

文章目录 题目分析题目链接 题目分析 来源:acwing 分析:这道题是第三次做了。 和PAT甲级1079 Total Sales of Supply Chain:[C++题解] 树、结点到根结点的距离、树形dp、记忆化搜索是同一题,题解思路请移步。 ac代码 #include<bits/stdc++.h>using namespace std;const int

1106. Lowest Price in Supply Chain 解析

是一个求最短链的问题,后面一个输出的是最短链的条数。 #include <iostream>#include <vector>#include <map>#include <cstring>#include <climits>#define MAX 100010using namespace std;int n;double p, r;vector <int> chain[M

PAT_A 1106. Lowest Price in Supply Chain (25)

1106. Lowest Price in Supply Chain (25) 题目信息 A supply chain is a network of retailers(零售商), distributors(经销商), and suppliers(供应商)-- everyone involved in moving a product from supplier to customer.St

PTA甲级 1106 Lowest Price in Supply Chain (25分)

强烈推荐,刷PTA的朋友都认识一下柳神–PTA解法大佬 本文由参考于柳神博客写成 柳神的CSDN博客,这个可以搜索文章 柳神的个人博客,这个没有广告,但是不能搜索 还有就是非常非常有用的 算法笔记 全名是 算法笔记 上级训练实战指南 //这本都是PTA的题解算法笔记 PS 今天也要加油鸭 题目原文 A supply chain is a network of retai

LeetCode 236 -- 二叉树的最近公共祖先 ( Lowest Common Ancestor of a Binary Tree ) ( C语言版 )

题目描述 :  方法一: 代码如下(附有解析): /*** Definition for a binary tree node.* struct TreeNode {* int val;* struct TreeNode *left;* struct TreeNode *right;* };*/struct TreeNode* FindNode(struct T

1143. Lowest Common Ancestor (30) 最近公共祖先

1143. Lowest Common Ancestor (30) 时间限制 200 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue The lowest common ancestor (LCA) of two nodes U and V in a tree is

C++标准模板(STL)- 类型支持 (数值极限,min,lowest,max)

数值极限 提供查询所有基础数值类型的性质的接口 定义于头文件 <limits> template< class T > class numeric_limits; numeric_limits 类模板提供查询各种算术类型属性的标准化方式(例如 int 类型的最大可能值是 std::numeric_limits<int>::max() )。   辅助类 指示浮点舍入模式 std::f

个人练习-PAT甲级-1106 Lowest Price in Supply Chain

题目链接https://pintia.cn/problem-sets/994805342720868352/problems/994805362341822464 题目大意:给出批发商和零售商的树状关系,每一次中转价格提高r%,求可能从零售商处获得的最低价格。 思路:就是DFS,零售商就是叶子结点。 完整代码 #include <iostream>#include <cstdio>#i