Problem Description “Point, point, life of student!” This is a ballad(歌谣)well known in colleges, and you must care about your score in this exam too. How many points can you get? Now, I told you the
题目 给出一个长度是 n n n的序列 A A A,构造出一个长度为 n n n的单调不递减序列 B B B,使 ∑ i = 1 n a b s ( A [ i ] − B [ i ] ) \sum_{i=1}^nabs(A[i]-B[i]) ∑i=1nabs(A[i]−B[i])最小 分析 设 f [ i ] [ j ] f[i][j] f[i][j]表示完成前 i i i个数的构造
「POJ 3666」Making the Grade 路面修整 1 算法标签 dp动态规划,滚动数组优化 2 题目难度 提高/提高+ 3 题面 「POJ 3666」Making the Grade 路面修整 4 分析题面 4.1 简要描述 给出数列 A A A, 求非严格单调不上升或单调不下降, 且 S = ∑ i = 1 N ∣ A i − B i ∣ S=\sum^N_{i=
Problem Description “Point, point, life of student!” This is a ballad(歌谣)well known in colleges, and you must care about your score in this exam too. How many points can you get? Now, I told you the
题意:N个(1<=N<=10^6)蘑菇,每个蘑菇相应的重量wi (0 < wi < 200),每个蘑菇的分数为 s = 10000 - (100 - wi) ^ 2,输出出现频率最大的 s;如果出现频率最大的 s 有多个并且还有其他小的出现频率的分数,则对于出现频率最大的 s,按 s 的大小从小到大依次输出;如果出现频率最大的 s 有多个并且没有其他小的出现频率了,则输出"Bad Mushroom
论文阅读:Multi-Grade Deep Learning for Partial Differential Equations with Applications to the Burgers Equation Multi-Grade Deep Learning for Partial Differential Equations with Applications to the Bur