B. New Year Permutation time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output User ainta has a permutation p1, p2, ..., pn.
今天开始学学最短路 现在从最开始的开始学 floyed(0(n3)) 感觉floyed 有动态规划的思想 通过枚举来把到每个点的最小价格算出来 然后保存到数组中 上例题 hdu 1690 Bus System Bus System Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Oth
There is a path graph G=(V,E)G=(V,E) with nn vertices. Vertices are numbered from 11 to nnand there is an edge with unit length between ii and i+1i+1 (1≤i<n)(1≤i<n). To make the graph more interesting
畅通工程续 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 30339 Accepted Submission(s): 11078 Problem Description 某省自从实行了很多年的畅通工程计划后,终
最短路 Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 37265 Accepted Submission(s): 16214 Problem Description 在每年的校赛里,所有进入决赛的同学都会获得一
传送门:http://blog.csdn.net/thestoryofsnow/article/details/6822576 作用:检测一个链表是否有环,如果有环,求出环的起点 int *head=list.GetHead();//链表起点 if(head!=null){//起初,快的和慢的都在链表起点 int *fast=head;int *slow=head;bool isCircul
思路: 初看此题,n<=50直接用floyed写,我用了三维数组f[i][j][0/1]表示从i到j有没有用减半的最短距离,然后floyed来求最短路就好了,然后变量要开double,因为折半要除以2,会出现0.5的情况 C o d e Code Code: #include <cstdio>#include <iostream>#include <cstring>#de
题目描述 N (1 ≤ N ≤ 100) cows, conveniently numbered 1…N, are participating in a programming contest. As we all know, some cows code better than others. Each cow has a certain constant skill rating that