理论部分 假设给定直线段的起点坐标 ( x 0 , y 0 ) (x_0,y_0) (x0,y0)和终点坐标 ( x 1 , y 1 ) (x_1,y_1) (x1,y1),则该直线的直线方程为: y = k x + b y=kx + b y=kx+b 其中 k = y 1 − y 2 x 2 − x 1 , b = y 0 − k x 0 k=\frac{y_1-y_2}{x_2-x
参考1:https://www.bilibili.com/video/BV1cd4y1U7TC/?spm_id_from=333.999.0.0&vd_source=5b4cd3f84aab3b0261aa6b6791252d89参考2:https://blog.csdn.net/u013378269/article/details/103555482 CMakelist + Win32 A
文章目录 SummaryAuthentication procedureRetrieval of ICC Public KeyDynamic Data AuthenticationReference Summary Refer to dump.js and EMV SDA Test, continue to test on DDA. The DDA test result is