WGS84、GCJ02、BD09地图坐标系间的坐标转换及坐标距离计算

本文主要是介绍WGS84、GCJ02、BD09地图坐标系间的坐标转换及坐标距离计算，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

1、常见基本坐标简介

2、虽然GCJ02和BD09对原始地球坐标进行了转换加密，但是仍可以通过浏览器找到转换方法

基本参数

public static double pi = 3.1415926535897932384626;
public static double a = 6378245.0;
public static double ee = 0.00669342162296594323;

火星坐标转百度坐标

/*** 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换算法 将 GCJ-02 坐标转换成 BD-09 坐标*/
public static Gps gcj02_To_Bd09(double gg_lat, double gg_lon) {double x = gg_lon, y = gg_lat;double z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * pi);double theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * pi);double bd_lon = z * Math.cos(theta) + 0.0065;double bd_lat = z * Math.sin(theta) + 0.006;return new Gps(bd_lat, bd_lon);
}

百度坐标转火星坐标

/*** 火星坐标系 (GCJ-02) 与百度坐标系 (BD-09) 的转换算法 将 BD-09 坐标转换成GCJ-02 坐标*/
public static Gps bd09_To_Gcj02(double bd_lat, double bd_lon) {double x = bd_lon - 0.0065, y = bd_lat - 0.006;double z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * pi);double theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * pi);double gg_lon = z * Math.cos(theta);double gg_lat = z * Math.sin(theta);return new Gps(gg_lat, gg_lon);
}

地球坐标转火星坐标

/*** 地球坐标系 (WGS84) 与火星坐标系 (GCJ-02) 的转换算法 将 WGS84 坐标转换成 GCJ-02 坐标*/
public static Gps gps84_To_Gcj02(double lat, double lon) {if (outOfChina(lat, lon)) {return null;}double dLat = transformLat(lon - 105.0, lat - 35.0);double dLon = transformLon(lon - 105.0, lat - 35.0);double radLat = lat / 180.0 * pi;double magic = Math.sin(radLat);magic = 1 - ee * magic * magic;double sqrtMagic = Math.sqrt(magic);dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);double mgLat = lat + dLat;double mgLon = lon + dLon;return new Gps(mgLat, mgLon);
}

火星坐标转地球坐标

/*** 地球坐标系 (WGS84) 与火星坐标系 (GCJ-02) 的转换算法 将 GCJ-02 坐标转换成 WGS84 坐标*/
public static Gps gcj_To_Gps84(double lat, double lon) {Gps gps = transform(lat, lon);double lontitude = lon * 2 - gps.getWgLon();double latitude = lat * 2 - gps.getWgLat();return new Gps(latitude, lontitude);
}

辅助方法

public static boolean outOfChina(double lat, double lon) {if (lon < 72.004 || lon > 137.8347) return true;if (lat < 0.8293 || lat > 55.8271) return true;return false;
}
private static Gps transform(double lat, double lon) {if (outOfChina(lat, lon)) return new Gps(lat, lon);double dLat = transformLat(lon - 105.0, lat - 35.0);double dLon = transformLon(lon - 105.0, lat - 35.0);double radLat = lat / 180.0 * pi;double magic = Math.sin(radLat);magic = 1 - ee * magic * magic;double sqrtMagic = Math.sqrt(magic);dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);double mgLat = lat + dLat;double mgLon = lon + dLon;return new Gps(mgLat, mgLon);
}
private static double transformLat(double x, double y) {double ret = -100.0 + 2.0 * x + 3.0 * y + 0.2 * y * y + 0.1 * x * y+ 0.2 * Math.sqrt(Math.abs(x));ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;ret += (20.0 * Math.sin(y * pi) + 40.0 * Math.sin(y / 3.0 * pi)) * 2.0 / 3.0;ret += (160.0 * Math.sin(y / 12.0 * pi) + 320 * Math.sin(y * pi / 30.0)) * 2.0 / 3.0;return ret;
}
private static double transformLon(double x, double y) {double ret = 300.0 + x + 2.0 * y + 0.1 * x * x + 0.1 * x * y + 0.1* Math.sqrt(Math.abs(x));ret += (20.0 * Math.sin(6.0 * x * pi) + 20.0 * Math.sin(2.0 * x * pi)) * 2.0 / 3.0;ret += (20.0 * Math.sin(x * pi) + 40.0 * Math.sin(x / 3.0 * pi)) * 2.0 / 3.0;ret += (150.0 * Math.sin(x / 12.0 * pi) + 300.0 * Math.sin(x / 30.0 * pi)) * 2.0 / 3.0;return ret;
}

坐标距离计算

private final static double EARTH_RADIUS = 6378.137;//地球半径
private static double rad(double d) {return d * Math.PI / 180.0;
}
/*** 计算两点间距离* @return double 距离 单位公里,精确到米*/
public static double GetDistance(double lat1, double lng1, double lat2, double lng2) {double radLat1 = rad(lat1);double radLat2 = rad(lat2);double a = radLat1 - radLat2;double b = rad(lng1) - rad(lng2);double s = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a / 2), 2) +Math.cos(radLat1) * Math.cos(radLat2) * Math.pow(Math.sin(b / 2), 2)));s = s * EARTH_RADIUS;s = new BigDecimal(s).setScale(3, BigDecimal.ROUND_HALF_UP).doubleValue();return s;
}

转载自：

http://nightfarmer.github.io/2016/12/01/GPSUtil/

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