本文主要是介绍计算两个经纬度之间的实际距离(Haversine公式)----c++,希望对大家解决编程问题提供一定的参考价值,需要的开发者们随着小编来一起学习吧!
来源:https://www.open-open.com/lib/view/open1430573897802.html
原理亦可参考:https://blog.csdn.net/gaocuisheng/article/details/126060795
#include <cmath>
#define EARTH_RADIUS 6371.0;// 地球半径,单位千米static double HaverSin(double theta)
{double v = sin(theta / 2);return v * v;
}static double ConvertDegreesToRadians(double degrees)
{return degrees * M_PI / 180;
}/// <summary>/// 计算2个经纬度之间的距离/// </summary>/// <param name="from_lon">起始点经度</param>/// <param name="from_lat">起始点纬度</param>/// <param name="to_lon">目标点经度</param>/// <param name="to_lat">目标点纬度</param>/// <returns></returns>
static double TwoPointToDistance(double from_lon, double from_lat, double to_lon, double to_lat)
{// 用 haversine 公式计算球面两点间的距离。// 经纬度转换成弧度from_lon = ConvertDegreesToRadians(from_lon);from_lat = ConvertDegreesToRadians(from_lat);to_lon = ConvertDegreesToRadians(to_lon);to_lat = ConvertDegreesToRadians(to_lat);// 差值double vLon = std::abs(from_lon - to_lon);double vLat = std::abs(from_lat - to_lat);// h is the great circle distance in radians, great circle 就是一个球体上的切面,它的圆心即是球心的一个周长最大的圆。double h = HaverSin(vLat) + cos(from_lat) * cos(to_lat) * HaverSin(vLon);auto sh = sqrt(h);double distance = 2 * (asin(sqrt(h))) * EARTH_RADIUS;// 将距离转换为米distance *= 1000;return distance;
}int main() {// 39.94607,116.32793 31.24063,121.42575std::cout << TwoPointToDistance(39.94607, 116.32793, 31.24063, 121.42575) << " meters" << std::endl;return 0;
}
这篇关于计算两个经纬度之间的实际距离(Haversine公式)----c++的文章就介绍到这儿,希望我们推荐的文章对编程师们有所帮助!