本文主要是介绍古老的五子棋,希望对大家解决编程问题提供一定的参考价值,需要的开发者们随着小编来一起学习吧!
午休忽然想起我奶奶喜欢下的一种古老的五子棋游戏,于是花了半小时开发出来了~
源代码:
<!DOCTYPE html>
<html lang="zh-CN">
<head><meta charset="UTF-8"><meta name="viewport" content="width=device-width, initial-scale=1.0"><title>棋盘图案</title><style>body {display: flex;justify-content: center;align-items: center;height: 100vh;margin: 0;background-color: #faf1c0;}canvas {background-color: #DAA520; /* 黄棕色 */border: 1px solid black;}</style>
</head>
<body><canvas id="chessboard" width="600" height="600"></canvas><script>const canvas = document.getElementById('chessboard');const ctx = canvas.getContext('2d');// 棋子信息存储let pieces = [];// 棋盘信息存储let board = { size: canvas.width, margin: canvas.width * 0.05, step: (canvas.width - canvas.width * 0.1) / 4 };board.drawableSize = board.size - 2 * board.margin;// 当前拖拽的棋子let currentPiece = null;function drawPiece(x, y, color, isDragging = false) {const radius = board.size / 28; // 棋子的半径,可以根据需要调整ctx.beginPath();ctx.arc(x, y, radius, 0, Math.PI * 2);ctx.fillStyle = color;ctx.fill();if (isDragging) {ctx.strokeStyle = 'red';ctx.stroke();}ctx.closePath();return { x, y, radius, color };}function drawChessboard() {ctx.clearRect(0, 0, board.size, board.size);for (let i = 0; i <= 4; i++) {ctx.moveTo(board.margin, board.margin + i * board.step);ctx.lineTo(board.margin + board.drawableSize, board.margin + i * board.step);ctx.moveTo(board.margin + i * board.step, board.margin);ctx.lineTo(board.margin + i * board.step, board.margin + board.drawableSize);}let size = board.sizelet step = board.steplet margin = board.margin// 画对角线ctx.moveTo(margin, margin);ctx.lineTo(size-margin, size-margin);ctx.moveTo(margin, size-margin);ctx.lineTo(size-margin, margin);ctx.moveTo(margin, 2*step+margin);ctx.lineTo(2 * step+margin, size-margin);ctx.moveTo(2*step+margin, margin);ctx.lineTo(size-margin, 2 * step+margin);ctx.moveTo(margin, 2 * step+margin);ctx.lineTo(2 * step+margin, margin);ctx.moveTo(2*step+margin, size-margin);ctx.lineTo(size-margin, 2*step+margin);ctx.stroke();ctx.stroke();}// 初始化棋子function initPieces() {pieces = [];// 画白色棋子for (let i = 0; i <= 4; i++) {pieces.push(drawPiece(i * board.step + board.margin, board.margin, 'white'));}// 画黑色棋子for (let i = 0; i <= 4; i++) {pieces.push(drawPiece(i * board.step + board.margin, board.size - board.margin, 'black'));}}// 检测坐标是否在棋子上function isPieceUnderCoordinate(x, y, piece) {const distance = Math.sqrt((x - piece.x) ** 2 + (y - piece.y) ** 2);return distance < piece.radius;}// 开始拖拽canvas.onmousedown = function(event) {const rect = canvas.getBoundingClientRect();const x = event.clientX - rect.left;const y = event.clientY - rect.top;for (const piece of pieces) {if (isPieceUnderCoordinate(x, y, piece)) {currentPiece = piece;break;}}};// 拖拽移动canvas.onmousemove = function(event) {if (currentPiece) {const rect = canvas.getBoundingClientRect();const x = event.clientX - rect.left;const y = event.clientY - rect.top;drawChessboard();for (const piece of pieces) {if (piece === currentPiece) {drawPiece(x, y, piece.color, true);} else {drawPiece(piece.x, piece.y, piece.color);}}}};// 放下棋子canvas.onmouseup = function(event) {if (currentPiece) {const rect = canvas.getBoundingClientRect();const x = event.clientX - rect.left;const y = event.clientY - rect.top;// 计算最接近的交点const closestX = Math.round((x - board.margin) / board.step) * board.step + board.margin;const closestY = Math.round((y - board.margin) / board.step) * board.step + board.margin;// 更新棋子位置currentPiece.x = closestX;currentPiece.y = closestY;drawChessboard();for (const piece of pieces) {drawPiece(piece.x, piece.y, piece.color);}}currentPiece = null;};// 双击切换棋子颜色canvas.ondblclick = function(event) {const rect = canvas.getBoundingClientRect();const x = event.clientX - rect.left;const y = event.clientY - rect.top;for (const piece of pieces) {if (isPieceUnderCoordinate(x, y, piece)) {// 切换颜色piece.color = piece.color === 'white' ? 'black' : 'white';// 重新绘制棋盘和棋子drawChessboard();for (const piece of pieces) {drawPiece(piece.x, piece.y, piece.color);}break;}}};drawChessboard();initPieces();</script>
</body>
</html>
效果图:
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