HLJUOJ1003（预处理）

Digital clock use 4 digits to express time, each digit is described by 3*3 characters (including”|”,”_”and” “).now given the current time, please tell us how can it be expressed by the digital clock.

There are several test cases.

Each case contains 4 integers in a line, separated by space.

Proceed to the end of file.

For each test case, output the time expressed by the digital clock such as Sample Output.

The digits showed by the digital clock are as follows:_  _     _  _  _  _  _  _ | _| _||_||_ |_   ||_||_|| |||_  _|  | _||_|  ||_| _||_|

解题思路：

	题意要求把相应的数字转换成时钟对应的图形输出。

	首先预处理出0~9所有数字的图形，这里很多细节，比如每个数字占三个位置，如果是1的话，前面两个补空格什么的····具体详见代码···此处坑无限多

完整代码：

#include <functional>
#include <algorithm>
#include <iostream>
#include <fstream>
#include <sstream>
#include <iomanip>
#include <numeric>
#include <cstring>
#include <climits>
#include <cassert>
#include <complex>
#include <cstdio>
#include <string>
#include <vector>
#include <bitset>
#include <queue>
#include <stack>
#include <cmath>
#include <ctime>
#include <list>
#include <set>
#include <map>
using namespace std;#pragma comment(linker, "/STACK:102400000,102400000")typedef long long LL;
typedef double DB;
typedef unsigned uint;
typedef unsigned long long uLL;/** Constant List .. **/ //{const int MOD = int(1e9)+7;
const int INF = 0x3f3f3f3f;
const LL INFF = 0x3f3f3f3f3f3f3f3fLL;
const DB EPS = 1e-9;
const DB OO = 1e20;
const DB PI = acos(-1.0); //M_PI;
const int maxn = 1001;
int a[4];string s1[maxn] = { " _ " , "   " , " _ " , " _ " , "   " , " _ " , " _ " , " _ " , " _ " , " _ " };
string s2[maxn] = { "| |" , "  |" , " _|" , " _|" , "|_|" , "|_ " , "|_ " , "  |" , "|_|" , "|_|" };
string s3[maxn] = { "|_|" , "  |" , "|_ " , " _|" , "  |" , " _|" , "|_|" , "  |" , "|_|" , " _|" };int main()
{#ifdef DoubleQfreopen("in.txt","r",stdin);#endifwhile(cin >> a[0] >>a[1] >> a[2] >> a[3]){for(int i = 0 ; i < 4 ; i ++)cout << s1[a[i]];cout << endl;for(int i = 0 ; i < 4 ; i ++)cout << s2[a[i]];cout << endl;for(int i = 0 ; i < 4 ; i ++)cout << s3[a[i]];cout << endl;}
}