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编写一个解决方案，报告那些买了 S8 而没有买 iPhone 的 买家。注意，S8 和 iPhone 是 Product 表中显示的产品。
题目连接：
https://leetcode.cn/problems/sales-analysis-ii/description/
建表插入数据：
Create table If Not Exists Product (product_id int, product_name varchar(10), unit_price int)
Create table If Not Exists Sales (seller_id int, product_id int, buyer_id int, sale_date date, quantity int, price int)
Truncate table Product
insert into Product (product_id, product_name, unit_price) values ('1', 'S8', '1000')
insert into Product (product_id, product_name, unit_price) values ('2', 'G4', '800')
insert into Product (product_id, product_name, unit_price) values ('3', 'iPhone', '1400')
Truncate table Sales
insert into Sales (seller_id, product_id, buyer_id, sale_date, quantity, price) values ('1', '1', '1', '2019-01-21', '2', '2000')
insert into Sales (seller_id, product_id, buyer_id, sale_date, quantity, price) values ('1', '2', '2', '2019-02-17', '1', '800')
insert into Sales (seller_id, product_id, buyer_id, sale_date, quantity, price) values ('2', '1', '3', '2019-06-02', '1', '800')
insert into Sales (seller_id, product_id, buyer_id, sale_date, quantity, price) values ('3', '3', '3', '2019-05-13', '2', '2800')画图分析：
代码实现：
with t1 as(selectbuyer_id,product_namefrom product p right join sales s on p.product_id=s.product_id)
select buyer_id from t1
where product_name='S8'group by buyer_idhaving buyer_id not in(select buyer_id from t1 where product_name='iPhone')
;总结：
将两个表进行连接，求出买了s8的买家，筛掉也买了iphone的买家
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