题意 求下式的值： Sn=⌈ (a+b√)n⌉%m S_n = \lceil\ (a + \sqrt{b}) ^ n \rceil\% m 其中： 0<a,m<215 0< a, m < 2^{15} 0<b,n<231 0 < b, n < 2^{31} (a−1)2<b<a2 (a-1)^2< b < a^2 解析 令： An=(a+b√)n A_n = (a +

【题目链接】 ：click here~~ 【题目大意】： 　A sequence Sn is defined as: Where a, b, n, m are positive integers.┌x┐is the ceil of x. For example, ┌3.14┐=4. You are to calculate Sn. 　　You, a top coder, say

So Easy!Time Limit: 1000ms, Special Time Limit:2500ms, Memory Limit:65536KBTotal submit users: 18, Accepted users: 8Problem 13150 : No special judgementProblem description A sequence Sn is defined

题目链接：hdu 4565 So Easy! 题目大意：计算题目中所给式子的值。 解题思路：矩阵快速幂。 An = (a+√b)^n, Bn = (a-√b)^n, Cn = An + Bn = (a+√b)^n+(a-√b)^n; 因为说An和Bn共轭，展开式可以互相抵消，所以保证说Cn一定是整数。 (a-1)^2 < b < a^2 -> a-1 < √b <

Problem Description 　　A sequence Sn is defined as: Where a, b, n, m are positive integers.┌x┐is the ceil of x. For example, ┌3.14┐=4. You are to calculate Sn. 　　You, a top coder, say: So easy!

So Easy! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4352    Accepted Submission(s): 1421 Problem Description A sequence S n is

点击打开链接 本题题意： 给出整数a,b,n,m求出Sn。 l0<a, m < 2 15, (a-1) 2<b < a 2, 0 < b, n < 2 31 解题思路： 因为a，b，n很大所以如果直接求(a+sqrt(b))^n会爆double范围 所以只能对公式化简。由题中b的范围为(a-1) 2<b < a 2   知道(a-1)<sqrt(b)<a,所以我们