过山车 Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7615 Accepted Submission(s): 3320 Problem Description RPG girls今天和大家一起去游乐场玩
过山车 Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 35605 Accepted Submission(s): 15159 Problem Description RPG girls今天和大家一起去游乐场玩,终于可以坐上梦
题目链接 #include<iostream>using namespace std;const int N = 1e5+7;int nums[N];int main(){int n, k, x;cin>>n;for(int i = 0; i < n; i++){cin>>nums[i];}cin >> k;while(k--){cin >> x;int l = 0, r = n -1;
过山车 Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 11509 Accepted Submission(s): 5066 Problem Description RPG girls今天和大家一起去游乐场玩,终于可
http://acm.split.hdu.edu.cn/showproblem.php?pid=2063 过山车 Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 18847 Accepted Submission(s):
过山车 Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 16742 Accepted Submission(s): 7314 Problem Description RPG girls今天和大家一起去游乐场玩,
话说POJ这完全背包的题并不多,而且这个也不是很裸,因为股票的价格都是1000的倍数,所以价格都除以1000,整个背包的容量也除以1000, 这样复杂度就降下来了,然后每年的话,由于有收益,所以背包容量还会变化 基本原理参考背包问题九讲。其核心部分与0-1背包中里面那层循环是反过来的 F[0::V ] = 0 for i = 1 to N for v = Ci to V F[v] = max(
过山车 Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 19553 Accepted Submission(s): 8527 Problem Description RPG girls今天和大家一起去游乐场玩,终