传送门:http://acm.hdu.edu.cn/showproblem.php?pid=5336 XYZ and Drops Time Limit: 3000/1500 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 1024 Accepted Submissio
传送门:http://acm.hdu.edu.cn/showproblem.php?pid=5335 Walk Out Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 2280 Accepted Submission(s):
传送门:http://acm.hdu.edu.cn/showproblem.php?pid=5327 Olympiad Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 442 Accepted Submission(s):
叛逆的小明 Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others) Total Submission(s): 81 Accepted Submission(s): 61 Problem Description 叛逆期的小明什么都喜欢反着做,连看数字也是如此(负号除外),
这里是paoxiaomo,一个现役ACMer,之后将会持续更新算法笔记系列以及笔试题题解系列 本文章面向想打ICPC/蓝桥杯/天梯赛等程序设计竞赛,以及各个大厂笔试的选手 感谢大家的订阅➕ 和 喜欢💗 有什么想看的算法专题可以私信博主 (本文题面由清隆学长收集) 01.K小姐的旅行预算计划 题目描述 K小姐计划去欧洲旅行,她的旅行预算总额为 k k k 欧元。旅行期间,她打算在交
This way 题意: 给你一个长度为n的排列,你每次可以取一个长度为3的子串,然后消掉最大和最小的数,直到最终剩下一个数,问你每个数是否可能是那个数。 题解: 那么我们肯定是枚举每个数,然后查看有多少数大于他,有多少数小于它。如果这些是相同的,那么每次就可以找连续三个数使得有一个大于它,一个小于它,然后直到消到最后。 那么如果不相同,我们就可以消掉连续三个大于它或者连续三个小于它中的
题目描述 Chiaki is interested in an infinite sequence a1, a2, a3, ..., which defined as follows: Chiaki would like to know the sum of the first n terms of the sequence, i.e. . As this number may be very
题目描述 There's a beautiful garden whose size is n x m in Chiaki's house. The garden can be partitioned into n x m equal-sized square chunks. There are some kinds of flowers planted in each square chunk
题目描述 The mode of an integer sequence is the value that appears most often. Chiaki has n integers a1,a2,...,an. She woud like to delete exactly m of them such that: the rest integers have only one mod
商汤科技致力于引领人工智能核心“深度学习”技术突破,构建人工智能、大数据分析行业解决方案。作为一家人工智能公司,用机器自动地解决各类实际问题自然不在话下。近日,商汤科技推出了一套安全令牌,令牌如下图所示: 安全令牌上的小孔有 nn 行 mm 列,不过有些行和有些列已经用导线整体焊接了,共有 kk 根导线。 我们可以在安全令牌上 不重叠 地焊接若干个小芯片,每个芯片需要在相邻(不能斜着相邻,
Ancient Distance 题目描述 输入描述 输出描述 For each test case, you should output the sum of all answers instead of each of them. 输入 31 231 1 输出 32 说明 The answer for the first test case is {2,1,
题目链接:点我啊╭(╯^╰)╮ 题目大意: n n n 个集合,每次查询一个值,该区间的所有集合都能用子集表示出这个值 解题思路: 区间每个集合都能表示出一个值,就是线性基的交 然后用线段树维护一下区间就完事了 核心:线性基求交的模板题 #include<bits/stdc++.h>#define rint register int#define deb(
历时五年,The Open Group旗下IT4IT™论坛重磅推出新一代标准——IT4IT™标准3.0版本快照正式面世。为了加深业界专家及高校教师对IT4IT™标准的学习和理解,紧跟数字生态系统管理的前沿实践,TheOpenGroup现推出“IT4IT™标准读书会”活动,邀请首批资深专家前来分享IT4IT™v3.0快照读后感,并结合自身经验为业界同行抛砖引玉。 10月26日晚,“IT4
Problem Description Kazari remembered that she had an expression s0 before. Definition of expression is given below in Backus–Naur form. ::= | ::= “+” | “*” ::= “0” | ::= “” | ::= “0” | ::= “