Description Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Solution 将两个有序链表合并成一个链表。(定义一个头结点,方便返回) /**
There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). 【算法思路】 搜了一下
leetcode-33. Search in Rotated Sorted Array 题目: Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target v
描述: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 分析: 如果第一个链表为空,则返回第二个链表如果第二个链表为空,就返回第一个链表(都为空会返回空
问题:https://leetcode.com/problems/two-sum-ii-input-array-is-sorted/?tab=Description Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a sp
Question: Follow up for "Search in Rotated Sorted Array": What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target
题目连接:Leetcode 108 Convert Sorted Array to Binary Search Tree 解题思路:每次取范围中间的数作为当前结点的值。 /*** Definition for a binary tree node.* struct TreeNode {* int val;* TreeNode *left;* TreeNode *righ
一、问题描述: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 二、解决思路: 平衡BST的话,位于中间位置的节点当做ROOT, 可以保证平衡。中间节点的左边元素为左子树右边元素为右子树,递归即可。 三、代码: package
一、问题描述: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Subscribe to see which companies asked this question 二、解决思路: Merge k Sorted Lists 属于
题目: Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. For example, Given 1->2->3->3->4->4->5, return 1->2->5. Given 1-
题目: Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 题解: 递归。 C++版: class Solution {public:TreeNode* sortedListToBST(ListNode* head)
Question 23. Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 中文:合并k个有序的链表,然后返回一个有序的链表的表头结点。 解决思路: 1) 模仿两个链表的做法: 用一个链表数组Li
Question 21. Merge Two Sorted Lists Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 中文:合并两个有序的链表,然后返回新的链
Question 88. Merge Sorted Array Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. 中文: 给定两个有序的整型数组num1和num2,将num2合并进num1,成为一个新的数组。 Note: You may assume tha
给定一个排序的数组,进行数组旋转之后引出了一系列的问题,这里将遇到的相关问题做一个总结,并给出解决方法,备用所需。 有序数组旋转操作 这个问题是所有系列问题的起始,给一个有序数组,使用这个操作进行旋转,得到的数组就可以以之为其他问题的基础进行引申。 Rotate an array of n elements to the right by k steps. For example, wi