题目 思路:因为有走的过程不能超初始位置1e5的限制,所以不能直接用奇数最多两次,4的倍数最多两次的结论。spfa,平方数的dis为1,然后推出其他数的dis #include<bits/stdc++.h>using namespace std;#define int long longconst int maxn = 2e5 + 5, inf = 1e9, N = 1e5;int a
jerry yue 介绍 (Introduction) Welcome to my third article. Today we will be looking at Jerry from HackTheBox. This is a realistic and very easy box. The article will again be similar to my first a