increasing专题

[LeetCode] 300. Longest Increasing Subsequence

题：https://leetcode.com/problems/longest-increasing-subsequence/description/ 题目 Given an unsorted array of integers, find the length of longest increasing subsequence. Example: Input: [10,9,2,5,3,7

CodeForces 490E Restoring Increasing Sequence

题意：一个严格递增序列某些数字的某些位被盖住了求恢复后的序列思路：贪心让每个数在大于前一个的基础上尽量的小先讨论数字长度 len[i]<len[i-1] 一定是NO len[i]>len[i-1] 除了第一位如果是？就填1以外其他？全填0 len[i]==len[i-1] dfs搜索num[i]格式下大于num[i-1]的最小的数代码： #include

leetcode第674题，Longest Continuous Increasing Subsequence

第674题，Longest Continuous Increasing Subsequence 题目： Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray). 本题的意思是给一个未排序的数组，求出数组中连续递增的序列的最大长度。

LeetCode contest 183 5376. 非递增顺序的最小子序列 Minimum Subsequence in Non-Increasing Order

Table of Contents 一、中文版二、英文版三、My answer 四、解题报告一、中文版给你一个数组 nums，请你从中抽取一个子序列，满足该子序列的元素之和严格大于未包含在该子序列中的各元素之和。如果存在多个解决方案，只需返回长度最小的子序列。如果仍然有多个解决方案，则返回元素之和最大的子序列。与子数组不同的地方在于，「数组的子序列」不强

杭电1423（Greatest Common Increasing Subsequence）

点击打开杭电1423 Problem Description This is a problem from ZOJ 2432.To make it easyer,you just need output the length of the subsequence. Input Each sequence is described with M - its lengt

HDU - 3030 Increasing Speed Limits

题意：求有长为m的序列生成的长度为n的序列的上升子序列的个数思路：生成完长为n的序列后，首先我们想到（nlogn）的求上升序列的方法，然后再这个基础上改进，每插入一个的时候，我们可以得到左边的小于它的个数，然后我们就可以得新增加的上升子序列是sum(id-1)+1,然后更新树状数组 #include <iostream>#include <cstdio>#include <cstri

[LeetCode] Increasing Triplet Subsequence

Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array. Formally the function should: Return true if there exists i, j, k such that arr[i] < arr[j]

Codeforces 490E Restoring Increasing Sequence(贪心)

题目链接：Codeforces 490E Restoring Increasing Sequence 每个数字在尽量满足的条件下尽量下的去构造即可。 #include <cstdio>#include <cstring>#include <algorithm>using namespace std;const int maxn = 1e5 + 5;const int maxm =

LeetCode刷题 | Day 2 最长严格递增或递减子列表（Longest Increasing or Decreasing SubList）

LeetCode刷题 | Day 2 最长严格递增或递减子列表（Longest Increasing Decreasing SubList）文章目录 LeetCode刷题 | Day 2 最长严格递增或递减子列表（Longest Increasing Decreasing SubList）前言一、题目概述二、解题方法2.1 动态规划思想2.1.1 思路讲解2.1.2 伪代码 + 逐步

*Leetcode 300. Longest Increasing Subsequence

https://leetcode.com/problems/longest-increasing-subsequence/description/ 经典的LIS。 O(n^2)的解法还是很直观的 class Solution {public:int lengthOfLIS(vector<int>& nums) {// int dp[nums.size()];int ans = 0;vect

Try increasing heap size with java option ‘-Xmxlt；sizegt；’(五十三)

1.报错解决编译内存不足，设置为4GB：# export JACK_SERVER_VM_ARGUMENTS="-Dfile.encoding=UTF-8 -XX:+TieredCompilation -Xmx4g"# ./prebuilts/sdk/tools/jack-admin kill-server # ./prebuilts/sdk/tools/jack-admin start

LeetCode *** 300. Longest Increasing Subsequence

题目： Given an unsorted array of integers, find the length of longest increasing subsequence. For example, Given [10, 9, 2, 5, 3, 7, 101, 18], The longest increasing subsequence is [2, 3, 7, 101], th

Codeforces Round 869 Div.1 A. Almost Increasing Subsequence 题解

Almost Increasing Subsequence 题面描述给定长度为 n n n 的一个序列 a a a 以及 q q q 次询问，每次询问给出 l l l 和 r r r，找出序列 a a a 在 [ l , r ] [l,r] [l,r] 内最长的几乎递增子序列，并输出其长度。几乎递增的定义：如果一个序列中不存在连续的三个数 x x x， y y y， z

[LeetCode] 300. Longest Increasing Subsequence @ python

一．题目：给一个数组，求它的最长递增子序列（不要求连续）的长度．二．解题思路：动态规划问题．dp[i]表示以nums[i]结尾的递增子序列的长度．需要用到双重循环．代码如下： class Solution(object):def lengthOfLIS(self, nums):""":type nums: List[int]:rtype: int"""if nums==[]:return

leetcode674-Longest Continuous Increasing Subsequence

题目给定一个未经排序的整数数组，找到最长且连续递增的子序列，并返回该序列的长度。连续递增的子序列可以由两个下标 l 和 r（l < r）确定，如果对于每个 l <= i < r，都有 nums[i] < nums[i + 1] ，那么子序列 [nums[l], nums[l + 1], …, nums[r - 1], nums[r]] 就是连续递增子序列。示例 1：输入：nums =

J - Greatest Common Increasing Subsequence

题目： This is a problem from ZOJ 2432.To make it easyer,you just need output the length of the subsequence. Input Each sequence is described with M - its length (1 <= M <= 500) and M integer numbers

hdu 1423 Greatest Common Increasing Subsequence 经典dp

// 最长公共上升子序列问题// 以f[i][j]表示a串前i个字符与b串前j个字符并且以b[j]为结尾匹配的状况// 为什么定义这个状态呢，因为我也是看到的百度文库中@我们都爱刘汝佳// 这篇文章中的介绍，发现这个状态真的非常好用// 状态转移方程// a[i]!=b[j]那么f[i][j] = f[i-1][j]，换而言之，我们可以直接丢掉a串中// 的a[i]不用考虑，这里和最长

(Nowcoder 2019国庆day5) E.Longest Increasing Subsequence（动态规划+思维）

传送门题意：f[i]是以i结尾的最长不下降子序列长度，问删掉第i个数后f[1]^2 xor f[3]^2 xor .. xor f[n]^2（不算第i个）解: 如果对最长不下降子序列理解的彻底的会觉得很简单吧，我们可以考虑到当不考虑一个数是，那有些f[i]可能会不受影响或者-1，但是我们如何快速得出呢。当然是先全部求一遍f[]了，然后我们需要一个mi[]数组，mi[i]定义为长度为i的不下

LeetCode329. Longest Increasing Path in a Matrix——动态规划

文章目录一、题目二、题解一、题目 Given an m x n integers matrix, return the length of the longest increasing path in matrix. From each cell, you can either move in four directions: left, right, up, or do

300. Longest Increasing Subsequence

300. Longest Increasing Subsequence class Solution:def lengthOfLIS(self, nums: List[int]) -> int:dp=[1 for i in range(len(nums)+1)]for i in range(len(nums)):for j in range(i-1,-1,-1):if nums[i]>nums[

Leetcode 300. Longest Increasing Subsequence [Python]

此题是众多LIS相关的母题目。很重要。两种思想求，贪心（NlogN）和DP（N方）贪心： class Solution:def lengthOfLIS(self, nums: List[int]) -> int:N = len(nums)res = [float('inf') for _ in range(N)]for i in range(len(nums)):idx = bisect.bi

Leetcode 300. Longest Increasing Subsequence [Python]

此题是众多LIS相关的母题目。很重要。两种思想求，贪心（NlogN）和DP（N方）贪心： class Solution:def lengthOfLIS(self, nums: List[int]) -> int:N = len(nums)res = [float('inf') for _ in range(N)]for i in range(len(nums)):idx = bisect.bi

Leetcode 2111. Minimum Operations to Make the Array K-Increasing [Python]

暴力求解subarray的LIS的方式在89个（89/92）TC处TLE class Solution:def kIncreasing(self, arr: List[int], k: int) -> int:subset = []res = 0for i in range(0, k):temp = []j = iwhile j < len(arr):temp.append(arr[j])j +

Leetcode 2111. Minimum Operations to Make the Array K-Increasing [Python]

暴力求解subarray的LIS的方式在89个（89/92）TC处TLE class Solution:def kIncreasing(self, arr: List[int], k: int) -> int:subset = []res = 0for i in range(0, k):temp = []j = iwhile j < len(arr):temp.append(arr[j])j +

674. Longest Continuous Increasing Subsequence

674. 最长连续递增序列给定一个未经排序的整数数组，找到最长且连续的的递增序列。示例 1: 输入: [1,3,5,4,7]输出: 3解释: 最长连续递增序列是 [1,3,5], 长度为3。尽管 [1,3,5,7] 也是升序的子序列, 但它不是连续的，因为5和7在原数组里被4隔开。示例 2: 输入: [2,2,2,2,2]输出: 1解释: 最长连续递增序列是 [2]

LeetCode //C - 300. Longest Increasing Subsequence

300. Longest Increasing Subsequence Given an integer array nums, return the length of the longest strictly increasing subsequence. Example 1: Input: nums = [10,9,2,5,3,7,101,18] Output: 4 Explan