Codeforces 490E Restoring Increasing Sequence(贪心)

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题目链接：Codeforces 490E Restoring Increasing Sequence

每个数字在尽量满足的条件下尽量下的去构造即可。

#include <cstdio>
#include <cstring>
#include <algorithm>using namespace std;
const int maxn = 1e5 + 5;
const int maxm = 10;int N, len[maxn];
char s[maxn][maxm];void init () {scanf("%d", &N);for (int i = 1; i <= N; i++)scanf("%s", s[i]);
}inline void fill(int d) {for (int i = 0; i < len[d]; i++)if (s[d][i] == '?')s[d][i] = (i == 0 ? '1' : '0');
}bool dfs (char* a, char* b, int d, int n) {if (d >= n)return false;if (b[d] != '?') {if (a[d] == b[d]

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