#include <stdio.h>int f(int x){return x?:1;}int main(){printf("f %d\n", f(0));printf("f %d\n", f(1));return 0;} And got the following output f 1f 1 And when I change it to int f(int x){r
准备工作: 创建一张表,联合主键: create table test_insert_on_duplicate_key_update(id tinyint unsigned not null,birth_day date not null,score int unsigned not null,primary key(id, birth_day)) engine = InnoDB;
Given an array of integers and an integer k, find out whether there there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between iand j is at most k. 题目意
错误: Error:Execution failed for task ':k-9:transformResourcesWithMergeJavaResForRelease'. > com.android.build.api.transform.TransformException: com.android.builder.packaging.DuplicateFileException: Du
在spark当中通常需要对mapPartitions内部进行计算,这样可以在不进行网络传输的情况下,对数据进行局部计算 而mapPartitions中的迭代器为Iterator scala中的Iterator只能进行一次迭代,使用过后就消失了,所以在mapPartitions中既不能两次遍历 如:一次mapPartitions求最大最小值 val it = Iterator(20, 4
问题描述: Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the absolute difference between i and j is at m
问题分描述: Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every el
问题描述: Given a binary tree, return all duplicate subtrees. For each kind of duplicate subtrees, you only need to return the root node of any one of them. Two trees are duplicate if they have the
java8 stream 的toMap方法,如果key有重复的就会跑出上面的异常,比如: List<Integer> list = new ArrayList<>();list.add(1);list.add(2);list.add(1);System.out.println(list.stream().collect(Collectors.toMap(e->e, e->"hel