What does `return x ? : 1` mean in C language? [duplicate] stackoverflow

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#include <stdio.h>
int f(int x)
{return x?:1;
}
int main()
{printf("f %d\n", f(0));printf("f %d\n", f(1));return 0;
}

And got the following output

f 1
f 1

And when I change it to

int f(int x)
{return x?:2;
}

I am getting

f 2
f 1

I just want to know whether this behavior (return 1 if nothing mentioned) is mentioned in the standard.

Answer：

The middle operand in a conditional expression may be omitted. Then if the first operand is nonzero, its value is the value of the conditional expression.

Therefore, the expression

 x ? : y

has the value of x if that is nonzero; otherwise, the value of y.

This example is perfectly equivalent to

 x ? x : y  

In this simple case, the ability to omit the middle operand is not especially useful. When it becomes useful is when the first operand does, or may (if it is a macro argument), contain a side effect. Then repeating the operand in the middle would perform the side effect twice. Omitting the middle operand uses the value already computed without the undesirable effects of recomputing it.

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