balanced专题

【HDU】3709 Balanced Number 数位DP

传送门：【HDU】3709 Balanced Number 题目分析：枚举重心的位置再进行数位DP。代码如下： #include <cstdio>#include <cstring>#include <algorithm>using namespace std ;typedef long long LL ;#pragma comment(linker, "/ST

分治，CF 1237C2 - Balanced Removals (Harder)

目录一、题目 1、题目描述 2、输入输出 2.1输入 2.2输出 3、原题链接二、解题报告 1、思路分析 2、复杂度 3、代码详解一、题目 1、题目描述 2、输入输出 2.1输入 2.2输出 3、原题链接 https://codeforces.com/problemset/problem/1237/C2

POJ3264 Balanced Lineup 线段树|ST表

Balanced Lineup Time Limit: 5000MS Memory Limit: 65536KTotal Submissions: 39453 Accepted: 18511Case Time Limit: 2000MS Description For the daily milking, Farmer John's N cows (1 ≤ N ≤ 50,000)

poj3264--Balanced Lineup(RMQ求最大最小)

Balanced Lineup Time Limit: 5000MS Memory Limit: 65536KTotal Submissions: 33665 Accepted: 15830Case Time Limit: 2000MS Description For the daily milking, Farmer John's N cows (1 ≤ N ≤ 50,000)

poj3274--Gold Balanced Lineup(hash)

Gold Balanced Lineup Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 12334 Accepted: 3618 Description Farmer John's N cows (1 ≤ N ≤ 100,000) share many similarities. In fact, FJ has

size balanced tree (平衡二叉树) ----- 傻X树----陈启峰论文

Size Balanced Tree(SBT)是一种平衡二叉查找树。它的论文由中国广东中山纪念中学的陈启峰于2006年底完成，并在Winter Camp 2007中发表。由于SBT的拼写很容易找到中文谐音，它常被中国的<

二分+ST表+递推，Cf 1237D - Balanced Playlist

一、题目 1、题目描述 2、输入输出 2.1输入 2.2输出 3、原题链接 Problem - 1237D - Codeforces 二、解题报告 1、思路分析 case3提示我们一件事情：如果存在某个位置永远不停止，那么所有位置都满足永远不停止很容易证明随着下标右移，区间最大值不会变大，那么后面2倍大于旧的最大值的数的二倍仍然大于新

LeetCode 题解（20）: Balanced Binary Tree

题目： Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never

Balanced Lineup （poj-3264）

RMQ解决方案： #include <iostream>#include <math.h>#define max(a,b) ((a>b)?a:b)#define min(a,b) (a<b?a:b)using namespace std;const int maxn=50001;int h[maxn];int mx[maxn][16],mn[maxn][16];int

关于Balanced-MixUp是自定义的交叉熵损失函数

Balanced-MixUp的自定义的交叉熵损失函数 def cross_entropy_loss(input: torch.Tensor,target: torch.Tensor) -> torch.Tensor:return -(input.log_softmax(dim=-1) * target).sum(dim=-1).mean() 官方的 nn.CrossEntropyLoss()

Influence-Balanced Loss 中的Resample策略

改进的sampler策略 elif args.train_rule == 'Resample':train_sampler = ImbalancedDatasetSampler(dset_train) class ImbalancedDatasetSampler(torch.utils.data.sampler.Sampler):def __init__(self, dataset,

【CF1924D】Balanced Subsequences 【卡特兰数，组合数，数学】

C F 1924 D . CF1924D. CF1924D.Balanced Subsequences 题意为：给定 n , m , k n,m,k n,m,k，求有多少个由 n n n 个 (， m m m 个 ) 组成的序列满足最长的合法括号子序列的长度恰为 2 k 2k 2k（对 1 0 9 + 7 10^9+7 109+7 取模）。思路我们很容易想到这跟 C a t

POJ 3264 Balanced Lineup RMQ / 线段树

题意：给出一个队列，找出指定区间的最大值与最小值。题解：RMQ, 注意边界需要理清楚。参考http://www.cnblogs.com/cnjy/archive/2009/08/30/1556566.html RMQ(Range Minimum/Maximum Query)问题： RMQ问题是求给定区间中的最值问题。当然，最简单的算法是O(n)的，但是对于查询次数很多（设

93.Balanced Binary Tree-平衡二叉树（容易题）

平衡二叉树题目给定一个二叉树,确定它是高度平衡的。对于这个问题,一棵高度平衡的二叉树的定义是：一棵二叉树中每个节点的两个子树的深度相差不会超过1。样例给出二叉树 A={3,9,20,#,#,15,7}, B={3,#,20,15,7} 二叉树A是高度平衡的二叉树，但是B不是题解递归计算任意节点左右子树的高度值进行比较。 /*** Definition of TreeNod

LeetCode - balanced-binary-tree

题目： Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never di

Balanced Lineup POJ-3264（线段树）

For the daily milking, Farmer John’s N cows (1 ≤ N ≤ 50,000) always line up in the same order. One day Farmer John decides to organize a game of Ultimate Frisbee with some of the cows. To keep things

Balanced Number 数位DP+ 枚举

传送门分析这道题跟我前段时间写的一道数位DP的思路有点一致，但是居然没想出来首先我们确定一下，任何一个平衡数的支点，都仅存在一个支点，所以，我们可以去枚举每一个支点，计算每一个支点下，平衡数的数量，然后相加即可最后只需要注意一下，如果每一位都取0，那么任何一位都可以作为支点，但合法的数字只有一个0，所以最后答案需要特殊处理一下代码 #include <iostream>#i

poj Balanced Lineup

http://poj.org/problem?id=3264 线段树板子题，由原来的维护区间和变成维护区间最大值和最小值即可。 #include<iostream>using namespace std;typedef long long ll;#define maxn 50007 #define ls l,m,rt<<1#define rs m+1,r,rt<<1|1int m

POJ 3264 Balanced Lineup (线段树单点更新区间查询)

Balanced Lineup Time Limit: 5000MS Memory Limit: 65536KTotal Submissions: 36820 Accepted: 17244Case Time Limit: 2000MS Description For the daily milking, Farmer John's N cows (1 ≤ N ≤ 5

POJ 3264 Balanced Lineup (RMQ模板)

Balanced Lineup Time Limit: 5000MS Memory Limit: 65536KTotal Submissions: 65283 Accepted: 30409Case Time Limit: 2000MS Description For the daily milking, Farmer John's N cows (1 ≤ N ≤ 50,000) alway

B树（Balanced-tree）

B-树是一种多路搜索树（并不一定是二叉的）。如果有更多的分支，那么就有更少的高度。这样，31个节点的理想二叉树（perfect binary tree）有5层，而31个节点的5叉树则只有3层，一颗M叉查找树可以有M路分支。随着分支增加，树的深度在减小。一颗完全二叉树（complete binary tree）的高度大约为log2N，而一颗完全M叉树（complete M-ary tree）的高

leetcode - 1963. Minimum Number of Swaps to Make the String Balanced

Description You are given a 0-indexed string s of even length n. The string consists of exactly n / 2 opening brackets ‘[’ and n / 2 closing brackets ‘]’. A string is called balanced if and only if:

POJ 3264 Balanced Lineup 线段树

A - Balanced Lineup For the daily milking, Farmer John's N cows (1 ≤ N ≤ 50,000) always line up in the same order. One day Farmer John decides to organize a game of Ultimate Frisbee with some of t

Balanced Number HDU - 3709

http://acm.hdu.edu.cn/showproblem.php?pid=3709 dp[i][j]代表[i+1,pos-1]的权值和为j时 [0,i]能提供多少解 #include <cstdio>#include <cstring>#include <algorithm>using namespace std;typedef long long ll;const

AVL树（balanced binary search tree)

#include<stdio.h>#include<stdlib.h>typedef int Item;typedef struct node* Tree;struct node /*AVL树结点定义*/{Item val;int height;struct node* left;struct node* right;};/**************

Codeforces Round #544 (Div. 3) C. Balanced Team(二分)

题目链接：http://codeforces.com/contest/1133/problem/C 题意：是给了n个数，让你找出m个数，使得这m个数中的最大值减去最小值不大于5，求最大的m。思路：sort一下，然后二分找到第一个不大于5的下标，求个最大值即可。 #include<bits/stdc++.h>using namespace std;const int N = 1e6+7;