使用linux，c++，创作一个简单的五子棋游戏

本文主要是介绍使用linux，c++，创作一个简单的五子棋游戏，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

#include <iostream>  
#include <vector>  
#include <unordered_map>  using namespace std;  // 棋盘大小  
const int BOARD_SIZE = 15;  // 棋子类型  
enum ChessType {  EMPTY,  BLACK,  WHITE  
};  // 棋盘类  
class ChessBoard {  
private:  vector<vector<ChessType>> board;  public:  ChessBoard() {  board.resize(BOARD_SIZE, vector<ChessType>(BOARD_SIZE, EMPTY));  }  // 打印棋盘  void print() {  for (int i = 0; i < BOARD_SIZE; ++i) {  for (int j = 0; j < BOARD_SIZE; ++j) {  switch (board[i][j]) {  case BLACK: cout << "● "; break;  case WHITE: cout << "○ "; break;  default: cout << "· "; break;  }  }  cout << endl;  }  }  // 下棋  bool placeChess(ChessType type, int x, int y) {  if (x < 0 || x >= BOARD_SIZE || y < 0 || y >= BOARD_SIZE || board[x][y] != EMPTY) {  return false;  }  board[x][y] = type;  return true;  }  // 检查是否胜利  bool checkWin(ChessType type, int x, int y) {  // 检查八个方向（上下左右，四个对角线）  vector<pair<int, int>> directions = {{-1, 0}, {1, 0}, {0, -1}, {0, 1},  {-1, -1}, {-1, 1}, {1, -1}, {1, 1}};  for (auto dir : directions) {  int count = 1;  for (int i = 1; i < 5; ++i) {  int nx = x + i * dir.first;  int ny = y + i * dir.second;  if (nx >= 0 && nx < BOARD_SIZE && ny >= 0 && ny < BOARD_SIZE && board[nx][ny] == type) {  ++count;  } else {  break;  }  }  for (int i = 1; i < 5; ++i) {  int nx = x - i * dir.first;  int ny = y - i * dir.second;  if (nx >= 0 && nx < BOARD_SIZE && ny >= 0 && ny < BOARD_SIZE && board[nx][ny] == type) {  ++count;  } else {  break;  }  }  if (count >= 5) {  return true;  }  }  return false;  }  
};  int main() {  ChessBoard board;  ChessType currentPlayer = BLACK;  bool gameOver = false;  while (!gameOver) {  board.print();  cout << (currentPlayer == BLACK ? "Black" : "White") << ", enter your move (x y): ";  int x, y;  cin >> x >> y;  if (board.placeChess(currentPlayer, x, y)) {  if (board.checkWin(currentPlayer, x, y)) {  board.print();  cout << (currentPlayer == BLACK ? "Black wins!" : "White wins!") << endl;  gameOver = true;  } else {  currentPlayer = (currentPlayer == BLACK) ? WHITE : BLACK;  }  } else {  cout << "Invalid move. Try again." << endl;  }  }  return 0;  
}

编译通过后的执行效果：