本文主要是介绍Day62.算法训练，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！
718. 最长重复子数组
class Solution {public int findLength(int[] nums1, int[] nums2) {int max = 0;int[][] dp = new int[nums1.length][nums2.length];for (int i = 0; i < nums1.length; i++) {for (int j = 0; j < nums2.length; j++) {if (nums1[i] == nums2[j]) {if (i == 0 || j == 0) {dp[i][j] = 1;} else {dp[i][j] = dp[i - 1][j - 1] + 1;}if (dp[i][j] > max) {max = dp[i][j];}}}}// for (int[] ints : dp) {// System.out.println(Arrays.toString(ints));// }return max;}
}300. 最长递增子序列
class Solution {public int lengthOfLIS(int[] nums) {int[] dp = new int[nums.length];Arrays.fill(dp, 1);int max = 1;for (int i = 1; i < nums.length; i++) {for (int j = 0; j < i; j++) {if (nums[i] > nums[j]) {dp[i] = Integer.max(dp[i], dp[j] + 1);if (dp[i] > max) {max = dp[i];}}}}return max;}
}674. 最长连续递增序列
class Solution {public int findLengthOfLCIS(int[] nums) {int[] dp = new int[nums.length];Arrays.fill(dp, 1);int max = 1;for (int i = 1; i < nums.length; i++) {if (nums[i - 1] < nums[i]) {dp[i] = dp[i - 1] + 1;if (dp[i] > max) {max = dp[i];}}}// System.out.println(Arrays.toString(dp));return max;}
}1143. 最长公共子序列
class Solution {public int longestCommonSubsequence(String text1, String text2) {int[][] dp = new int[text1.length() + 1][text2.length() + 1];char[] chars1 = text1.toCharArray();char[] chars2 = text2.toCharArray();for (int i = 1; i < chars1.length + 1; i++) {for (int j = 1; j < chars2.length + 1; j++) {if (chars1[i - 1] == chars2[j - 1]) {dp[i][j] = dp[i - 1][j - 1] + 1;} else {dp[i][j] = Integer.max(dp[i - 1][j], dp[i][j - 1]);}}}return dp[chars1.length][chars2.length];}
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