黑龙江省2010年省赛

2024-08-31 00:58

文章标签 2010 省赛黑龙江省

本文主要是介绍黑龙江省2010年省赛，希望对大家解决编程问题提供一定的参考价值，需要的开发者们随着小编来一起学习吧！

数论题+打表题，因子和，模板打就好。

1008: Friends number

时间限制: 1 Sec 内存限制: 128 MB
提交: 360 解决: 99
[ 提交 ][ 状态 ][ 讨论版 ]

题目描述

Paula and Tai are couple. There are many stories between them. The day Paula left by airplane, Tai send one message to telephone 2200284, then, everything is changing… (The story in “the snow queen”).

After a long time, Tai tells Paula, the number 220 and 284 is a couple of friends number, as they are special, all divisors of 220’s sum is 284, and all divisors of 284’s sum is 220. Can you find out there are how many couples of friends number less than 10,000. Then, how about 100,000, 200,000 and so on.

The task for you is to find out there are how many couples of friends number in given closed interval [a,b]。

输入

There are several cases.

Each test case contains two positive integers a, b(1<= a <= b <=500,000).

Proceed to the end of file.

输出

For each test case, output the number of couples in the given range. The output of one test case occupied exactly one line.

样例输入

1 100#include<cstdio>
#include<iostream>
#include<cmath>
#include<cstdlib>
#include<algorithm>
#include<cstring>
using namespace std;
int main()
{int a,b;int sum=0;while(scanf("%d%d",&a,&b)!=EOF){sum=0;if(a<=220&&b>=284)sum++;if(a<=1184&&b>=1210)sum++;if(a<=2620&&b>=2924)sum++;if(a<=5020&&b>=5564)sum++;if(a<=6232&&b>=6368)sum++;if(a<=10744&&b>=10856)sum++;if(a<=12285&&b>=14595)sum++;if(a<=17296&&b>=18416)sum++;if(a<=63020&&b>=76084)sum++;if(a<=66928&&b>=66992)sum++;if(a<=67095&&b>=71145)sum++;if(a<=69615&&b>=87633)sum++;if(a<=79750&&b>=88730)sum++;if(a<=100485&&b>=124155)sum++;if(a<=122265&&b>=139815)sum++;if(a<=122368&&b>=123152)sum++;if(a<=141664&&b>=153176)sum++;if(a<=142310&&b>=168730)sum++;if(a<=171856&&b>=176336)sum++;if(a<=176272&&b>=180848)sum++;if(a<=185368&&b>=203432)sum++;if(a<=196724&&b>=202444)sum++;if(a<=280540&&b>=365084)sum++;if(a<=308620&&b>=389924)sum++;if(a<=319550&&b>=430402)sum++;if(a<=356408&&b>=399592)sum++;if(a<=437456&&b>=455344)sum++;if(a<=469028&&b>=486178)sum++;if(a<=503056&&b>=514736)sum++;if(a<=522405&&b>=525915)sum++;if(a<=600392&&b>=669688)sum++;if(a<=609928&&b>=686072)sum++;if(a<=624184&&b>=691256)sum++;if(a<=635624&&b>=712216)sum++;if(a<=643336&&b>=652664)sum++;if(a<=667964&&b>=783556)sum++;if(a<=726104&&b>=796696)sum++;if(a<=802725&&b>=863835)sum++;if(a<=879712&&b>=901424)sum++;if(a<=898216&&b>=980984)sum++;if(a<=947835&&b>=1125765)sum++;if(a<=998104&&b>=1043096)sum++;if(a<=1077890&&b>=1099390)sum++;if(a<=1154450&&b>=1189150)sum++;if(a<=1156870&&b>=1292570)sum++;if(a<=1175265&&b>=1438983)sum++;if(a<=1185376&&b>=1286744)sum++;if(a<=1280565&&b>=1340235)sum++;if(a<=1328470&&b>=1483850)sum++;if(a<=1358595&&b>=1486845)sum++;if(a<=1392368&&b>=1464592)sum++;if(a<=1466150&&b>=1747930)sum++;if(a<=1468324&&b>=1749212)sum++;if(a<=1511930&&b>=1598470)sum++;if(a<=1669910&&b>=2062570)sum++;if(a<=1798875&&b>=1870245)sum++;if(a<=2082464&&b>=2090656)sum++;if(a<=2236570&&b>=2429030)sum++;if(a<=2652728&&b>=2941672)sum++;if(a<=2723792&&b>=2874064)sum++;if(a<=2728726&&b>=3077354)sum++;if(a<=2739704&&b>=2928136)sum++;if(a<=2802416&&b>=2947216)sum++;if(a<=2803580&&b>=3716164)sum++;if(a<=3276856&&b>=3721544)sum++;if(a<=3606850&&b>=3892670)sum++;if(a<=3786904&&b>=4300136)sum++;if(a<=3805264&&b>=4006736)sum++;if(a<=4238984&&b>=4314616)sum++;if(a<=4246130&&b>=4488910)sum++;if(a<=4259750&&b>=4445050)sum++;printf("%d\n",sum);}return 0;
}

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