本文主要是介绍UVA 11401 Triangle Counting,希望对大家解决编程问题提供一定的参考价值,需要的开发者们随着小编来一起学习吧!
中文详解请访问我的博客:http://xiaoshig.sinaapp.com/?p=128
You are given n rods of length 1, 2…, n. You have to pick any 3 of them & build a triangle. How many distinct triangles can you make? Note that, two triangles will be considered different if they have at least 1 pair of arms with different length.
Input
The input for each case will have only a single positive integer n (3<=n<=1000000). The end of input will be indicated by a case with n<3. This case should not be processed.
Output
For each test case, print the number of distinct triangles you can make.
Sample Input Output for Sample Input
5 8 0 | 3 22 |
#include<iostream>
#include<algorithm>
using namespace std;
unsigned long long f[1000010],i,n;
int main()
{f[3]=0;for(i=4;i<=1000000;i++)f[i]=f[i-1]+((i-1)*(i-2)/2-(i-1)/2)/2;while(cin>>n&&n>=3){cout<<f[n]<<endl;}
return 0;
}
这篇关于UVA 11401 Triangle Counting的文章就介绍到这儿,希望我们推荐的文章对编程师们有所帮助!