OpenCV Lesson 3 : Mask operations on matrices

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矩阵上的掩码运算

Mask operations on matrices are quite simple. The idea is that we recalculate each pixel’s value in an image according to a mask matrix (also known as kernel). This mask holds values that will adjust how much influence neighboring pixels (and the current pixel) have on the new pixel value. From a mathematical point of view we make a weighted average, with our specified values.
矩阵上的掩模运算非常简单。这个想法是我们根据掩模矩阵（也称为内核）重新计算图像中每个像素的值。该掩码保存的值将调整相邻像素（和当前像素）对新像素值的影响程度。从数学的角度来看，我们使用指定的值进行加权平均值。

Let’s consider the issue of an image contrast enhancement method.
让我们考虑图像对比度增强方法的问题。

$$I(i,j)=5\ast I(i,j)-[I(i-1,j)+I(i+1,j)+I(i,j-1)+I(i,j+1)]$$

$$⟺I(i,j)\ast M,whereM=\begin{array}{cccc}i/j& -1& 0& +1\\ -1& 0& -1& 0\\ 0& -1& 5& -1\\ +1& 0& -1& 0\end{array}$$

The first notation is by using a formula, while the second is a compacted version of the first by using a mask. You use the mask by putting the center of the mask matrix (in the upper case noted by the zero-zero index) on the pixel you want to calculate and sum up the pixel values multiplied with the overlapped matrix values. It’s the same thing, however in case of large matrices the latter notation is a lot easier to look over.
第一个表示法是使用公式，而第二个表示法是使用掩码的第一个表示法的压缩版本。您可以通过将掩码矩阵的中心（以零零索引表示的大写字母）放在要计算的像素上来使用掩码，并将像素值与重叠矩阵值相乘求和。这是同样的事情，但是在大型矩阵的情况下，后一种表示法更容易查看。

Built-in filter2D

First, we load one image

cv::Mat dst0, dst1;
cv::Mat src = imread( "Lena.png", IMREAD_GRAYSCALE);

Then, we need a kernel

    Mat kernel = (Mat_<char>(3,3) <<  0, -1,  0,-1,  5, -1,0, -1,  0);

Finally, do filter2D

filter2D( src, dst1, src.depth(), kernel );

Hand written

void Sharpen(const Mat& myImage,Mat& Result)
{CV_Assert(myImage.depth() == CV_8U);  // accept only uchar imagesconst int nChannels = myImage.channels();Result.create(myImage.size(),myImage.type());for(int j = 1 ; j < myImage.rows-1; ++j){const uchar* previous = myImage.ptr<uchar>(j - 1);const uchar* current  = myImage.ptr<uchar>(j    );const uchar* next     = myImage.ptr<uchar>(j + 1);uchar* output = Result.ptr<uchar>(j);for(int i= nChannels;i < nChannels*(myImage.cols-1); ++i){output[i] = saturate_cast<uchar>(5*current[i]-current[i-nChannels] - current[i+nChannels] - previous[i] - next[i]);}}Result.row(0).setTo(Scalar(0));Result.row(Result.rows-1).setTo(Scalar(0));Result.col(0).setTo(Scalar(0));Result.col(Result.cols-1).setTo(Scalar(0));
}

Use getTickCount(), and getTickFrequency() get the time passed

t = ((double)getTickCount() - t)/getTickFrequency();

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