HDU-2602 Bone Collector 01背包

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Bone Collector

Problem Description
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

Input
The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

Output
One integer per line representing the maximum of the total value (this number will be less than 231).

Sample Input

1
5 10
1 2 3 4 5
5 4 3 2 1

Sample Output

14

典型的01背包

#include<iostream>
#include<cstdio>
#include<string.h>
using namespace std;
int value[1010],liqud[1010];
int ans[1010];
int n,v;
int work()
{for(int i=1;i<=n;++i)for(int j=v;j>=liqud[i];--j)ans[j]=max(ans[j],ans[j-liqud[i]]+value[i]);return ans[v];
}int main()
{int t;scanf("%d",&t);while(t--){memset(ans,0,sizeof(ans));scanf("%d%d",&n,&v);for(int i=1;i<=n;++i)scanf("%d",&value[i]);for(int i=1;i<=n;++i)scanf("%d",&liqud[i]);printf("%d\n",work());}
}

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