本文主要是介绍LeetCdoe Minimum Path Sum,希望对大家解决编程问题提供一定的参考价值,需要的开发者们随着小编来一起学习吧!
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
题意:求从左上角到右下角最小的花费。思路:简单的dp。
class Solution {
public:int f[1000][1000];int minPathSum(vector<vector<int> > &grid) {if (grid.size() == 0 || grid[0].size() == 0) return 0;f[0][0] = grid[0][0];for (int i = 1; i < grid[0].size(); i++)f[0][i] = f[0][i-1] + grid[0][i];for (int i = 1; i < grid.size(); i++)f[i][0] = f[i-1][0] + grid[i][0];for (int i = 1; i < grid.size(); i++)for (int j = 1; j < grid[0].size(); j++)f[i][j] = min(f[i-1][j], f[i][j-1]) + grid[i][j];return f[grid.size()-1][grid[0].size()-1];}
};
这篇关于LeetCdoe Minimum Path Sum的文章就介绍到这儿,希望我们推荐的文章对编程师们有所帮助!