3278专题

BFS —— POJ 3278 Catch That Cow

对应POJ题目:点击打开链接 Catch That Cow Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 54686 Accepted: 17096 Description Farmer John has been informed of the location of a fugitive cow

POJ 3278 简单 BFS

这道题 挺有意思 每次有 3 中移动方式,可以前可以后。 问最少移动几次可以抓住牛。 不管是棋盘上怎么移动,这都是个最短路的问题。 而每次的权又都是1 ,完全可以用 BFS 来解决。 我觉得 BFS 中的 used 数组可以用 dist 来代替。 #include <iostream>#include <stdio.h>#include <algorithm>#include

poj_3278_Catch That Cow_201407241728

Catch That Cow Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 45959 Accepted: 14400 Description Farmer John has been informed of the location of a fugitive cow and wants to catch h

poj 3278 bfs

如图:http://poj.org/problem?id=3278    广搜 #include<iostream> using namespace std; #include<queue> int visited[100004]; struct node {     int num;     int count;     node(int n,int m)     {

C - Catch That Cow POJ - 3278(一维BFS)

Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He starts at a point N (0 ≤ N ≤ 100,000) on a number line and the cow is at a point K (0 ≤ K ≤ 100,0

POJ 3278-- Catch That Cow

题目: Catch That Cow Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 76114 Accepted: 24036 Description Farmer John has been informed of the location of a fugitive cow and wants t

POJ - 3278 Catch That Cow (BFS)

在很久很久以前,有一位大师级程序员,实力高强,深不可测,代码能力无人能及。从来没有人听说过他的真名,只知道他在完成一段代码后,总会跟上一行注释“十四出品,必属精品”,于是他在编程江湖上便有了绰号“十四”。   然而,十四大师并不满足于现有的一切,他想要让自己的实力有更进一步的提升。为此,他专程前往二次元世界修行。   二次元旅程归来的十四大师学习了新的技能——闪现。   在一条既定的直线

poj 3278 广搜

Catch That Cow Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 70333 Accepted: 22115 Description Farmer John has been informed of the location of a fugitive cow and wants to catch h

【POJ No. 3278】抓住那头牛 Catch That Cow

【POJ No. 3278】抓住那头牛 Catch That Cow POJ题目地址 【题意】 约翰希望立即抓住逃亡的牛。当前约翰在节点N ,牛在节点K (0≤N , K ≤100 000)时,他们在同一条线上。约翰有两种交通方式:步行和乘车。如果牛不知道有人在追赶自己,原地不动,那么约翰需要多长时间才能抓住牛? 步行:约翰可以在一分钟内从任意节点X 移动到节点X -1或X+1。乘车:

Catch That Cow(广度搜索 poj 3278)

Catch That Cow(点击转到) Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 119275 Accepted: 37221Description Farmer John has been informed of the location of a fugitive cow and wants to catch her

POJ 3278 Catch That Cow -----BFS

Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 115640 Accepted: 36125 Description Farmer John has been informed of the location of a fugitive cow and wants to catch her immediately. He st

poj 3278 Catch That Cow 【bfs】

Catch That Cow Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 52335 Accepted: 16416 Description Farmer John has been informed of the location of a fugitive cow and wants to cat

POJ 3278 Catch That Cow 【BFS】

题目链接:http://poj.org/problem?id=3278 题意:假设一个人在位置x,那么他下一分钟能到达的位置是x-1,x+1,2*x,现给出你n,k,让你求从n到k最少所花费的时间 解析:直接bfs #include <iostream>#include <cstdio>#include <cstring>#include <algorithm>#include <c