3268专题
POJ - 3268 Silver Cow Party （往返最短路，Floyd，Dijkstra 2次优化）
题目传送门 题意：求往返最短路的最大值。 1、先想到Floyd结果超时了。 2、先用1次Dijkstra求出各点到X的距离，然后再用N-1次算出X到各点的距离。 485ms AC。 3、先用1次Dijkstra算各点到X的距离，然后用相反的邻接表的Dijkstra算出点X到各点的距。 0ms AC了！ 直接Floyd：TLE #define _CRT_SECURE_N
poj 3268 Silver Cow Party(单源最短路径Dijkstra·最小环)
题目：http://acm.hust.edu.cn/vjudge/problem/viewProblem.action?id=11757 Silver Cow Party Time Limit: 2000MS Memory Limit: 65536KB 64bit IO Format: %I64d & %I64u Submit Status Description
POJ 3268 Silver Cow Party (来回最短路 SPFA)
Silver Cow Party Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 14384 Accepted: 6490 Description One cow from each of N farms (1 ≤ N ≤ 1000) conveniently numbered 1..N is goin
【POJ】 3268 Silver Cow Party
Silver Cow Party Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 16290 Accepted: 7460 Description One cow from each of N farms (1 ≤ N ≤ 1000) conveniently numbered 1..N is going to
poj 3268 SPFA
Silver Cow Party Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 18421 Accepted: 8434 Description One cow from each of N farms (1 ≤ N ≤ 1000) conveniently numbered 1..N is going
[Poj 3268][Usaco2007 Feb]Cow Party奶牛派对
[Usaco2007 Feb]Cow Party奶牛派对 时间限制: 1 Sec 内存限制: 128 MB 题目描述 农场有N(1≤N≤1000)个牛棚，每个牛棚都有1只奶牛要参加在X牛棚举行的奶牛派对．共有M(1≤M≤100000)条单向路连接着牛棚，第i条踣需要Ti的时间来通过．牛们都很懒，所以不管是前去X牛棚参加派对还是返回住所，她们都采用了用时最少的路线．那么，用时最多的奶牛需要多少
POJ-3268 Silver Cow Party（最短路spfa算法）
POJ-3268 Silver Cow Party Silver Cow Party Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 19989 Accepted: 9128 Description One cow from each of N farms (1 ≤ N ≤ 1000) conveniently numbe