思路:对初始状态进行建树,然后这题就相当于查询第一个合法的位置,并且对其值进行修改,整个题目要求维护的是区间最大值,很显然可以使用线段树。 #include <bits/stdc++.h>using namespace std;const int N = 2e6 + 5;typedef long long ll;typedef pair<ll, ll> pll;typedef arra
Luck and Love Time Limit: 10000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 5382 Accepted Submission(s): 1344 Problem Description 世界上上最远的距离不是相
Watermelon Full of Water 时间限制(普通/Java):3000MS/9000MS 运行内存限制:65536KByte 描述 Watermelon is very popular in the hot summer. Students in ZJU-ICPC Team also love watermelon very much and they
Deal with numbers 时间限制(普通/Java):10000MS/30000MS 运行内存限制:65536KByte 描述 There are n numbers with the corresponding NO.1-n, and the value of the i-th number is xi. Define three operations:
不错的题目,这次不偷qsc得了,偷个别人的 https://blog.csdn.net/diogenes_/article/details/80396914 传送门 题目意思很简单,就是你有三种操作: 1 u v w 从u向v连一条权值为w的有向边 2 u L R w 从u向L至R的所有结点连一条权值为w的有向边 3 u L R w 从L至R的所有结点向u连一条权值为w的有向边 首
Color the ball Time Limit: 9000/3000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 5864 Accepted Submission(s): 3122 Problem Description N个气球排成一排,从