Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However,
PAT 甲级 1055 The World’s Richest 这道题一次AC,但是后来看《算法笔记·上机训练实战指南》中的解析,说由于M<100,所以每个年龄读入100个人,就可以不读入了,这样能显著提高时间,否则测试点二过不了。但是没有写这个预处理也过了,回去看了看时间是400ms,猜想应该是传参都用的是传引用调用,改成传值调用之后果然超时。 解析也是用传值调用写的,传引用不香吗。 #i
1036. Boys vs Girls (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue This time you are asked to tell the difference between the lowest grade of a
1056. Mice and Rice (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Mice and Rice is the name of a programming contest in which each programmer
1006. Sign In and Sign Out (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue At the beginning of every day, the first person who signs in the comp
1011. World Cup Betting (20) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue With the 2010 FIFA World Cup running, football fans the world over were
1051. Pop Sequence (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given a stack which can keep M numbers at most. Push N numbers in the order o
1042. Shuffling Machine (20) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Shuffling is a procedure used to randomize a deck of playing cards. Beca