思路 直接遍历链表即可,遇到val=0跳过,val非零则加在一起,最后返回即可 解题过程 返回链表可以有头结点,方便插入,返回head.next Code /*** Definition for singly-linked list.* public class ListNode {* int val;* ListNode next;* ListNode() {}*
应用场景 团队中两人同时fetch了一个分支。 第一个人修改后提交,第二个人提交就失败。失败信息如下: error: failed to push some refs to 'git@git.oschina.net:jacarrichan/jacarrichan.git' hint: Updates were rejected because the remote contains
split命令: for i in {1..30}; do num=$(printf "%05d\n" "$i");name="model-$num-of-00030.safetensors";split -b 3G $name tmp/$name-;echo $name;done 合并命令: for i in {1..30}; do num=$(printf "%05d\n" "$i")