ugly专题

LeetCode-Ugly Number

国电结束了,终于又有时间来刷题了,不过,这么多天不刷,有点不想再刷了的感觉。 今天来一道简单的,寻找丑数。 Write a program to check whether a given number is an ugly number. Ugly numbers are positive numbers whose prime factors only include 2, 3, 5.

lintcode Ugly Number II python

Description Ugly number is a number that only have factors 2, 3 and 5. Design an algorithm to find the nth ugly number. The first 10 ugly numbers are 1, 2, 3, 4, 5, 6, 8, 9, 10, 12... 利用动态规划的思想 de

Ugly Number问题及解法

问题描述: Write a program to check whether a given number is an ugly number. Ugly numbers are positive numbers whose prime factors only include 2, 3, 5. For example, 6, 8 are ugly while 14 is not ugly

C++备忘录081:std::make_move_iterator, ugly but might be worthwhile

std::make_move_iterator把*iterator的返回值转换成右值,可以一定情况下把拷贝变成移动 例如 auto v1 = std::vector<std::string>(cbegin(v0), cend(v0)); 改成 auto v1 = std::</

剑指Offer面试题34题:丑数(Ugly Number)(while循环里面的三个小问题)

语言:C/C++语言 IDE:    Mac/Xcode  丑数:我们把只包含因子2、3、5的数称为丑数(Ugly Number),求按照从小到大的顺序的第1500个丑数。例如6、8都是丑数,但14不是,因为它包含因子7。习惯我们把1当做第一个丑数。 分析:所谓一个数m是另一个数n的因子,是指n%m==0。根据丑数的定义,丑数能被2,3,5整除,也就是一个数能连续的被2整除,或者连续的被3整

LeetCode之旅(17)-Ugly Number

题目: Write a program to check whether a given number is an ugly number.Ugly numbers are positive numbers whose prime factors only include 2, 3, 5. For example, 6, 8 are ugly while 14 is not ugly since

LeetCode *** 313. Super Ugly Number

题目: Write a program to find the n th super ugly number. Super ugly numbers are positive numbers whose all prime factors are in the given prime list primes of size k. For example, [1, 2, 4, 7, 8, 13

0313super_ugly_number

0313超级丑数 题目 https://leetcode-cn.com/problems/super-ugly-number/ 方法一:最小堆 class Solution {public:int nthSuperUglyNumber(int n, vector<int>& primes) {//使用优先队列来构建最小堆,依次取出最小堆的堆顶元素,取n次priority_queue<lo

264 Ugly Number II

除第一个数 1 外,所有的Ugly Number都是有较小的Ugly Number乘2,3,5得到的, 所以本题的关键就是在 1*2,2*2,3*2,4*2,5*2,6*2,8*2… 1*3,2*3,3*3,4*3,5*3,6*3,8*3… 1*5,2*5,3*5,4*5,5*5,6*5,8*5… 之中找到第n个数。 public static int nthUglyNumber(in

LeetCode Ugly Number II

<span style="font-family: Arial, Helvetica, sans-serif; background-color: rgb(255, 255, 255);">题目:</span> Write a program to find the n-th ugly number. Ugly numbers are positive numbers whose

LeetCode Ugly Number

题目描述: Write a program to check whether a given number is an ugly number. Ugly numbers are positive numbers whose prime factors only include 2, 3, 5. For example, 6, 8 are ugly while 14 is not ug

264. Ugly Number II丑数

题目描述 把只包含因子2、3和5的数称作丑数(Ugly Number)。例如6、8都是丑数,但14不是,因为它包含因子7。 习惯上我们把1当做是第一个丑数。求按从小到大的顺序的第N个丑数。 解答 逐个判断每个整数是不是丑数,效率低 public:bool isUglyNumber(int num){while(num%2 == 0)num/=2;while(num%3 ==0)num/

[Lintcode]4. Ugly Number II/[Leetcode]264. Ugly Number II

4. Ugly Number II / 264. Ugly Number II 本题难度: MediumTopic: Data Structure Description Ugly number is a number that only have factors 2, 3 and 5. Design an algorithm to find the nth ugly number. Th

剑指offer---ugly number

把只包含因子2、3和5的数称作丑数(Ugly Number)。例如6、8都是丑数,但14不是,因为它包含因子7。 习惯上我们把1当做是第一个丑数。求按从小到大的顺序的第N个丑数。 解题思路:使用heap的方式进行排序处理,然后分别从其中向外取出数据。 java import java.util.HashSet;import java.util.PriorityQueue;import

UVA 136 POJ1338 Ugly Numbers

题目链接:POJ UVA 题目大意: Ugly numbers are numbers whose only prime factors are 2, 3 or 5. The sequence 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, … shows the first 10 ugly numbers. By convention, 1 is included. 把

[leetcode] 264. Ugly Number II (medium)

263. Ugly Number的子母题 题目要求输出从1开始数,第n个ugly number是什么并且输出。 一开始想着1遍历到n直接判断,超时了。 class Solution{public:bool isUgly(int num){while (num % 5 == 0 && num > 4)num /= 5;while (num % 3 == 0 && num > 2)num /=

VJ_Ugly Numbers_枚举

//#include<bits/stdc++.h>using namespace std;const int N=2222;int ans[N];int main(){int a,b,c,i;ans[0]=1;a=b=c=0;for( i=1;i<1500;i++ ){ans[i]=min( 2*ans[a],min( 3*ans[b],5*ans[c] ) );if(

136 - Ugly Numbers (UVA)

题目链接如下: Online Judge 这道题我看了刘汝佳的解法才写出来的……(暴力解法超时。另外还有一个非常简洁有趣的写法:UVA136-CSDN博客 学习一下。)代码如下: #include <cstdio>#include <time.h>#include <set>#include <queue>// #define debugconst int nbr = 1500;i