12. Integer to Roman Problem's Link ---------------------------------------------------------------------------- Mean: 将一个int型的整数转化为罗马数字. analyse: 没什么好说的,直接维基百科. Time complexity: O(
Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 罗马数字规则: 1, 罗马数字共有7个,即I(1)、V(5)、X(10)、L(50)、C(100)、D(500)和M(1000)。 罗马数字中没有“0”。
问题描述: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 问题分析: 我们根据罗马数的特点,从后往前循环字符串,若i代表的值小于i+1代表的值,sum值减小,否则就增加。 详见代码: class Solutio
问题描述: Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 问题分析: 本题目目的是将一个整数转换为罗马数字的表现形式。我们可以将能用的到罗马数字存到数组里,然后再调用。 详见代码: class Solut
Description Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. Solution 这个题只要知道转换规则,遍历一遍字符串就行。 class Solution {public:int romanToInt(stri
题目描述 Given an integer, convert it to a roman numeral.Input is guaranteed to be within the range from 1 to 3999. 思路 由于罗马数字就是由”个“”十“、”百“拼凑而来。因此我们只需要将下面几张表存储起来,然后查表即可 【罗马数字】1~9: {"I", "II", "III", "I
Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 分析: 将一个数字转化为罗马字符串表示。 大数左边加上小数就是把大数减去这个小数."M","CM","D","CD","C","XC","L","XL","X","I
题目描述: Given an integer, convert it to a roman numeral.Input is guaranteed to be within the range from 1 to 3999.Subscribe to see which companies asked this questionShow TagsShow Similar Problems 准
题目描述: Given a roman numeral, convert it to an integer.Input is guaranteed to be within the range from 1 to 3999.Subscribe to see which companies asked this question 预备知识: 记数方法 基本字符 I V X L C
一、问题描述 Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 二、问题分析 无 三、算法代码 public class Solution {public String intToRoman(int num)
problem 方法一,一位一位判断。 class Solution {public String intToRoman1(int num) {StringBuilder sb = new StringBuilder();char ooo[] = new char[]{'I','V','X','L','C','D','M'};int wei = 0;while(num>0){int n = n
【题目】 Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 【分析】 I = 1; V = 5; X = 10; L = 50; C = 100; D = 500; M = 1000; 还有一些特殊的:每两个阶段的
题目: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 链接:Roman to Integer 解法:用数组存字母表示的数 class Solution { public: int romanToInt(string
题目: Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. ps: I = 1; V = 5; X = 10; L = 50; C = 100; D = 500; M = 1000; 链接:Integer to R
题目要求 Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. Subscribe to see which companies asked this question package com.syy.leetcode13;pub