LeetCode13 Roman to Integer

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题目要求

Given a roman numeral, convert it to an integer.

Input is guaranteed to be within the range from 1 to 3999.

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package com.syy.leetcode13;public class solution {public int romanToInt(String s) {int sum = 0;//建立对应的函数与数字的对照关系int[] arr = new int[s.length()];for(int i = s.length() - 1; i >= 0; i--) {int temp = 0;switch(s.charAt(i)) {case 'I' :temp = 1;break;case 'V' :temp = 5;break;case 'X' :temp = 10;break;case 'L' :temp = 50;break;case 'C' :temp = 100;break;case 'D' :temp = 500;break;case 'M' :temp = 1000;break;}arr[i] = temp;}//拆分字符串if(arr.length == 1) {return arr[0];}sum = arr[arr.length - 1];for(int i = arr.length - 2; i >= 0 ; i--) {int temp = arr[i] >= arr[i + 1] ? arr[i] : -arr[i];sum += temp;}return sum;}
}

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