robber专题

[LeetCode] 213. House Robber II

题:https://leetcode.com/problems/house-robber-ii/description/ 题目 You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses at t

[LeetCode] 198. House Robber

题目内容 https://leetcode-cn.com/problems/house-robber/ You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stoppin

leetcode 198. House Robber(python3)

题目 :House Robber 题目分析: 强盗只能间隔着抢钱,连续抢就会被发现,当输入为【1,2,3,1】输出,1+3=4 ,输入为【2,7,9,3,1】输出为2+9+1=12 输入为【2,1,2,4】输出为2+4=6 编程思路: 1 .题目要求输入为列表,输出为整型 2.实际含义。 f(0) = nums[0] #输

Leetcode: House Robber

题目: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent

Leetcode 213 House Robber II

原题: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses at this place are arranged in a circle. That means the first house

LeetCode-House_Robber

题目: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacen

LeetCode213. House Robber II——动态规划

文章目录 一、题目二、题解 一、题目 You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses at this place are arranged in a circle. T

LeetCode2560. House Robber IV——二分答案+动态规划

文章目录 一、题目二、题解 一、题目 There are several consecutive houses along a street, each of which has some money inside. There is also a robber, who wants to steal money from the homes, but he refuses t

[LeetCode]198.House Robber

题目 You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent h

leetcode----213. House Robber II

链接: https://leetcode.com/problems/house-robber-ii/ 题意: 有一个小偷打算去一群居民家偷钱。这些居民的家是一个环(数组表示,数组中每个元素都为正,表示该居民家中有多少钱),规定若小偷同时偷了相邻两家的钱,则会触动警报系统。求小偷在不触动警报系统的前提下最大能偷到多少金额 思路: 由于是一个环,也就是最后一个元素的下一个元素是第一个元素。那

337. House Robber III(Leetcode每日一题-2020.08.05)

Problem The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the “root.” Besides the root, each house has one and only one parent house. Aft

House Robber III

这道题一开始的确不好转化到tree的处理,这个学习了,最重要的是下面的错误,同上一题II,从根节点出发,这个无法变化,但若是从子节点出发,就完全可以是从子节点(这时相当于根)出发,或者,从子节点的子节点出发,所以必须要比较大小 /*** Definition for a binary tree node.* public class TreeNode {* int val;*

House Robber II

这道题我们犯了两个大的错误: 1. 忘记数量为1和2的情况了; 2. 最关键的,我们一定要明确动归取值的意义。如此题,当start为0,表示可以从0这个位置开始,但从取值来看,未必就必须从0开始,如果1位置数值大,当然就可以从1开始,至于位置2,则是比较位置0加位置2的值和位置1的值,所以 /dp[1] = Math.max(dp[0], nums[1]);/一定得有。这才是动归。

house robber follow up

输出抢劫的house public static void main(String[] args) {// rob(new int[]{4,1,2,7,5,3,1});// rob(new int[]{1,1,3,6,7,10,7,1,8,5,9,1,4,4,3});// rob(new// int[]{183,219,57,193,94,233,202,154,65,240,97,234

leetcode笔记-House Robber

1.给定一个数组,相邻的两个数不能取,从头到尾能取到的和的最大值? 思路:动态规划            dp[i]=max(dp[i-1],dp[i-2]+nums[i])            dp[0]=nums[0];dp[1]=max(nums[0],nums[1])            class Solution {//动态规划dp[i]=max(dp[i-1],dp[i-

LeetCode //C - 198. House Robber

198. House Robber You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is

每日一练:“打家劫舍“(House Robber)问题 I

1. 问题   假设有一排房屋,每个房屋里都存放着一定数量的财宝。相邻的房屋装有相互连通的防盗系统,如果两个相邻的房屋在同一晚上被小偷闯入,系统会自动报警。   求解的问题是,小偷在不触发警报的情况下,一晚上最多能偷到多少财宝。 2. 解题思路(状态转移方程) 2.1 状态转移方程   状态转移方程是系统动力学中描述系统状态随时间演变的数学方程。这种方程通常用来表示系统的状态如何从一个

JAVA算法:House Robber IIIIII JAVA版本解题

JAVA算法:House Robber I&II&III JAVA版本解题 LeetCode198. House Robber https://leetcode.com/problems/house-robber/ LeetCode 213. House Robber II https://leetcode.com/problems/house-robber-ii/ LeetCode 337

JAVA算法:House Robber(JAVA版本解题)

JAVA算法:House Robber(JAVA版本解题) 题目描述: 你是一个专业的小偷,计划偷窃沿街的房屋。每间房内都藏有一定的现金,影响你偷窃的唯一制约因素就是相邻的房屋装有相互连通的防盗系统,如果两间相邻的房屋在同一晚上被小偷闯入,系统会自动报警。 给定一个代表每个房屋存放金额的非负整数数组,计算你在不触动警报装置的情况下,能够偷窃到的最高金额。 示例 1: 输入: [1,2,3