n,k=list(map(int,input().split()))a=list(map(int,input().split()))count=0sum=0for i in range(n):sum+=a[i]if(sum>=k):count+=1sum=0else :if(i==n-1):count+=1print(count)
n=int(input())a=list(map(int,input().split()))count=0for i in range(1,n-1):if((a[i]>a[i-1] and a[i]>a[i+1]) or (a[i]<a[i-1] and a[i]<a[i+1])):#既然是折点,那么就是折点附近的两个点大于、小于折点的值count = count + 1pri
n=int(input())a=list(map(int ,input().split()))before = a[0]count = 0for i in range(n):if(a[i]!=before):#数字之间发生变化就加一count = count + 1before = a[i]if(a[i]==before and i==n-1):#最后一个数字的情况count = co
n,m=map(int,input().split())a=[]for i in range(n):a.append(input().split())for i in range(m):for j in range(n):print(a[j].pop(),end=' ')print() 因为这道题呢,我研究了好久,我想着不能只逆时针旋转90度,万一以后碰到了各种旋转的度数。下面是
n=int(input())a=list(map(int,input().split()))a_count=[0 for i in range(n)]for i in range(n):a_count[a[i]]=a_count[a[i]]+1if(i!=n-1):print(a_count[a[i]],end=' ')else :print(a_count[a[i]])
Python100例 我的实现展示(1-5例) '''1、有四个数字:1、2、3、4,能组成多少个互不相同且无重复数字的三位数?各是多少?'''import mathdef test_exam_01():list_x = []for a in range(1, 5):for b in range(1, 5):if a != b:for c in range(1, 5):if a != c an
100+ Python challenging programming exercises 9 Question 81 Please write a program to randomly print a integer number between 7 and 15 inclusive. Hints: Use random.randrange() to a random integer