We all know the Super Powers ofthis world and how they manage to get advantages in political warfare or evenin other sectors. But this is not a political platform and so we will talkabout a different
题目链接 题目描述 设有一个长度为 n n n 的 V V V。初始时,所有的元素都为 0。 现在可以对数组 V V V 进行若干次操作,对于第 i i i 次操作如下( i i i从0 开始): 任选一个位置 p o s pos pos, p o s ∈ [ 1 , n ] pos∈[1, n] pos∈[1,n],然后执行 V p o s = V p o s + k i V_{
You are given n integers a1, a2, ..., an. Find the number of pairs of indexes i, j (i < j) that ai + aj is a power of 2 (i. e. some integer xexists so that ai + aj = 2x). Input The first line co
You are given n integers a1, a2, ..., an. Find the number of pairs of indexes i, j (i < j) that ai + aj is a power of 2 (i. e. some integer x exists so that ai + aj = 2x). Input The first line conta
题目描述: The Sum of the k-th Powers time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output There are well-known formulas: , , . Also mathematicians
题目:C. Factorials and Powers of Two 题意: 若一个数是2的次方,或是某个数的阶乘,则这个数为powerful数,给出一个数n,求n最少可表示为多少个powerful数的和 数据范围:。 思路: 1、任意一个数肯定可以表示成若干个2的次方数的和,因为把这个数转化成二进制形式,为
We all know the Super Powers of this world and how they manage to get advantages in political warfare or even in other sectors. But this is not a political platform and so we will talk about a differe
Vampiric Powers, anyone?—CF1847C 参考文章 这个思路完美利用了 a i a_i ai 很小的这个特点,通过异或前缀和完美地将循环数组的长度变为循环元素的范围,极快地提升了代码的效率。 思路 手推一遍“召唤”的过程可以发现,能召唤出的最大力量即 a a a 数组中连续子串中元素异或和的最大值。用代码表示就是: int res = a[1];for (i