题目意思：给出两个杯子容积，初始都为空杯子，给出目标水量，可以执行一些操作，分别是倒空一个杯子，倒满一个杯子，和将一个杯子的水倒到另一个中，问得到目标水量要进行至少多少次以及每次都是什么 FILL（1）表示倒满1杯子，POUR（2，1）表示将2杯子里的水倒进1杯子中，DROP（1）表示倒空1杯子。 本体为广度优先生成树，每次对六种操作进行广度搜索，用二维数组进行状态是否出现过的标记，并记录

问题描述： Pots of gold game: Two players A & B. There are pots of gold arranged in a line, each containing some gold coins (the players can see how many coins are there in each gold pot - perfect inform

Pots Description You are given two pots, having the volume of A and B liters respectively. The following operations can be performed: FILL(i) fill the pot i (1 ≤ i ≤ 2) from the tap; DROP(i) empty

You are given two pots, having the volume of A and B liters respectively. The following operations can be performed: FILL(i) fill the pot i (1 ≤ i ≤ 2) from the tap; DROP(i) empty the pot i to the dr

Description You are given two pots, having the volume of A and B liters respectively. The following operations can be performed: FILL(i)        fill the pot i (1 ≤ i ≤ 2) from the tap;DROP(i)

题意： 给两个不同容量的杯子，要求经过最少的操作使其中一个杯子中有cL水 要点： 也就是BFS题，只不过这题每个节点有6种方向 15304559Seasonal3414Accepted212K0MSC++2024B2016-03-23 19:34:10 #include<stdio.h>#include<string.h>#include<stdlib.h>#defin

1.题意：有两个罐子A,B,可以进行三种操作， FILL(i)        fill the pot i (1 ≤ i ≤ 2) from the tap;//把第i个罐子装满；DROP(i)      empty the pot i to the drain;//把第i个罐子清空；POUR(i,j)    pour from pot i to pot j; after this operat

1.题意：有两个罐子A,B,可以进行三种操作， FILL(i)        fill the pot i (1 ≤ i ≤ 2) from the tap;//把第i个罐子装满；DROP(i)      empty the pot i to the drain;//把第i个罐子清空；POUR(i,j)    pour from pot i to pot j; after this operat

3414 Pots 经典倒水问题，要求最短，宽搜，ax + by = c 有 解条件c = 0 (mod gcd(a,b)) #include  < iostream > #define  MAX_LEN 10001 using   namespace  std; int  a,b,c; bool  black[ 101 ][ 101 ] = ... {false} ; struct